[英]Javascript code— What's wrong with function ToppingsWanted()?
[英]What's wrong with this javascript code? (body script calling head function)
为什么以下结果没有任何效果? 我得到空白页。 我不断修改/简化代码,以查看问题出在哪里,并且似乎与该行有关。
"var count = NbnamePattern(names)"
当主体脚本调用在头中定义但未传递任何参数的函数时,事情似乎就起作用了。
<!DOCTYPE html> <html lang="en"> <head> <title>Assignment 2 Q4</title> <meta charset="utf-8" /> <script> function NbnamePattern(var names) { var count = 0; for (var i in names) { if (names[i].search(/ie$/) != -1 || names[i].search(/y$/) != -1) count++; } return count; } </script> </head> <body> <p></p> <script type="text/javaScript"> var names = new Array("freddie", "bob", "mieke", "yahoo2", "georgey"); var count = NbnamePattern(names); document.getElementsByTagName("p")[0].innerHTML = "The number of names having these two patterns (/ie$/) and (/y$) in the array is:" + count; </script> </body> </html>
function NbnamePattern(var names){
var count = 0;
for(var i in names)
if(names[i].search(/ie$/) != -1 || names[i].search(/y$/) != -1)
count++;
return count;
}
应该
function NbnamePattern(names){
var count = 0;
for(var i in names)
if(names[i].search(/ie$/) != -1 || names[i].search(/y$/) != -1)
count++;
return count;
}
javascript中的函数不接受类型,应该只是名称
您需要从NbnamePattern(var names)
函数中删除var
<!DOCTYPE html> <html lang="en"> <head> <title>Assignment 2 Q4</title> <meta charset="utf-8" /> <script> function NbnamePattern(names) { var count = 0; for (var i in names) { if (names[i].search(/ie$/) != -1 || names[i].search(/y$/) != -1) count++; } return count; } </script> </head> <body> <p></p> <script type="text/javaScript"> var names = new Array("freddie", "bob", "mieke", "yahoo2", "georgey"); var count = NbnamePattern(names); document.getElementsByTagName("p")[0].innerHTML = "The number of names having these two patterns (/ie$/) and (/y$) in the array is:" + count; </script> </body> </html>
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