8 位和 16 位处理器如何通过两个寄存器访问更多 RAM? [英]How do 8-bit and 16-bit processors access more RAM with two registers?
如何在 x86 程序集中将 8 位地址移动到 16 位寄存器中? [英]How can I move an 8-bit address into a 16-bit register in x86 assembly?
如何计算两个包含8位值的数组的16位点积? [英]How do I compute the 16-bit dot product of two arrays containing 8-bit values?
如何在程序集中将带符号的8位字节转换为带符号的16位整数? [英]How do I convert a signed 8-bit byte to a signed 16-bit integer in assembly?