使用Ajax获得两个查询结果
[英]Get two query results with Ajax
问题描述
我可以从PHP服务器端得到两个结果吗？ 我希望在AJAX成功之后都填充数据和seta。
这是我的HTML和javascript代码：
<body>
<div align="center" id="box"></div>
<hr>
<div align="center" id="tox"></div>
<script src="jquery.js"></script>
<script>
$(document).ready(function(e) {
var SeeID = 89;
var SeeID2 = 88;
$.ajax({
type: 'POST',
url: "server.php",
data: "SeeID="+SeeID+"&SeeID2"+SeeID2,
success: function(data,seta){
$('#box').html(data);
$('#tox').html(seta);
}
});
});
</script>
</body>
这是我的PHP服务器端代码：
if (isset($_POST['SeeID'])) {
$SeeID = $_POST['SeeID'];
$QLoadFeild = $conn->query("SELECT * FROM myinfo WHERE id='".$SeeID."'");
$X = $QLoadFeild->fetch();
$name = $X['name'];
$family = $X['family'];
echo '<div>'.$name.'</div><div>'.$family.'</div>';
}
if (isset($_POST['SeeID2'])) {
$SeeID2 = $_POST['SeeID2'];
$QLoadFeild = $conn->query("SELECT * FROM myinfo WHERE id='".$SeeID2."'");
$X = $QLoadFeild->fetch();
$name = $X['name'];
$family = $X['family'];
echo '<div>'.$name.'</div><div>'.$family.'</div>';
}
1 个解决方案
解决方案1
0 2017-02-25 12:25:45
在PHP中，尝试将其推入数组并作为JSON值返回，
$outputArr = array();
if (isset($_POST['SeeID'])) {
$SeeID = $_POST['SeeID'];
$QLoadFeild = $conn->query("SELECT * FROM myinfo WHERE id='".$SeeID."'");
$X = $QLoadFeild->fetch();
$name = $X['name'];
$family = $X['family'];
$outputArr[] = '<div>'.$name.'</div><div>'.$family.'</div>';
}
if (isset($_POST['SeeID2'])) {
$SeeID2 = $_POST['SeeID2'];
$QLoadFeild = $conn->query("SELECT * FROM myinfo WHERE id='".$SeeID2."'");
$X = $QLoadFeild->fetch();
$name = $X['name'];
$family = $X['family'];
$outputArr[] = '<div>'.$name.'</div><div>'.$family.'</div>';
}
echo json_encode($outputArr);
并在JS Success函数中
success: function(data,seta){
var datas = JSON.stringify(data); // use it further
}
Ajax从SQL查询获取结果
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