从HTML表单传递的值不正确

Question

带有注释的表格提供了一系列使用选择表格进行选择的选项。 当从$ _POST数组中检索值时，尽管传递了正确的ID，但season的值似乎只是表格中的最后一个值。

我检查了我的代码，据我所知，联赛未在其他任何地方进行更新。

我确定我缺少明显的东西，但无法弄清楚！

<form method = 'post' action = 'index.php?choice=matcht&stage=1'><table width = '50%' border = '1'><thead><tr>
<th>Select</th>
<th>League</th>
<th>Season</th>
</tr></thead>
<tr><td><input type = 'radio' name = 'id' value = '1' ></td>
<td><input type = 'text' name = 'league' value = 'MLB21'  readonly></td>
<td><input type = 'text' name = 'season' value = '12'  readonly></td>
</tr>
<tr><td><input type = 'radio' name = 'id' value = '25' ></td>
<td><input type = 'text' name = 'league' value = 'MLB21'  readonly></td>
<td><input type = 'text' name = 'season' value = '13'  readonly></td>
</tr>
<tr><td><input type = 'radio' name = 'id' value = '49' ></td>
<td><input type = 'text' name = 'league' value = 'MLB21'  readonly></td>
<td><input type = 'text' name = 'season' value = '14'  readonly></td>
</tr>
<tr><td><input type = 'radio' name = 'id' value = '73' ></td>
<td><input type = 'text' name = 'league' value = 'MLB21'  readonly></td>
<td><input type = 'text' name = 'season' value = '15'  readonly></td>
</tr>
<tr><td><input type = 'radio' name = 'id' value = '97' ></td>
<td><input type = 'text' name = 'league' value = 'MLB21'  readonly></td>
<td><input type = 'text' name = 'season' value = '16'  readonly></td>
</tr>
<tr><td colspan = '3' align = 'center'><input type = 'submit' name = 'go' value = 'GO'></td></tr>
</table>
</form>

这是生成HTML的PHP​​：

  $sql='SELECT  `TeamID`, `League`,`Season` FROM teams WHERE `FranchiseID` = 0 GROUP BY `League`,`Season` ORDER BY `League` ASC ,`Season` ASC ';
  $unmatched = $db2->get_results($sql);

    if ($db2->num_rows>0) {

  echo "<form method = 'post' action = 'index.php?choice=matcht&stage=1'>";
  echo "<table width = '50%' border = '1'>";
  echo "<thead><tr>\n";
    echo "<th>Select</th>\n";
    echo "<th>League</th>\n";
    echo "<th>Season</th>\n";
  echo "</tr></thead>\n";
  foreach ( $unmatched as $unmatch )
  {
              // Access data using object syntax
              echo "<tr>";
                echo "<td><input type = 'radio' name = 'id' value = '$unmatch->TeamID' ></td>\n";
                echo "<td><input type = 'text' name = 'league' value = '".$unmatch->League."'  readonly></td>\n";
                echo "<td><input type = 'text' name = 'season' value = '".$unmatch->Season."'  ></td>\n";
              echo "</tr>\n";
  }

  echo "<tr><td colspan = '3' align = 'center'><input type = 'submit' name = 'go' value = 'GO'></td></tr>\n";
  echo "</table>\n";
  echo "</form>\n";

Answer 1

所有文本输入都具有相同的名称，而最后一个将覆盖其他输入。 使用一个数组并将索引设置为id以便您知道要获取哪些：

<tr><td><input type = 'radio' name = 'id' value = '1' ></td>
<td><input type = 'text' name = 'league[1]' value = 'MLB21'  readonly></td>
<td><input type = 'text' name = 'season[1]' value = '12'  readonly></td>

然后，您可以像这样获得它：

$id = $_POST['id'];
$league = $_POST['league'][$id];
$season = $_POST['season'][$id];