排名访问SQL Server 2014

Question

我有一个按ID进行医生就诊的样本表。 我希望按年龄对问题进行排名，并按ID进行划分，以便我可以按ID对同一问题的第2次和第3次访问进行一些统计计算。 请注意：我有一个更大的数据集，所以我正在寻找可以解决这个问题的东西。

到目前为止，我有

SELECT 
    ID, Age, Problem, COUNT(Problem) AS cnt,
    RANK() OVER (PARTITION BY id ORDER BY Problem, Age ASC) AS rnk
FROM
    #Test1
GROUP BY
    ID, Problem, Age
ORDER BY
    Age ASC

代码运行，但等级计算不正确。 请帮忙。

Answer 1

据我了解，您需要按ID和问题进行分区：

CREATE TABLE #Test1 (ID int, Problem nvarchar(20), Age int)

INSERT INTO #Test1
VALUES
(1,'Arm',50),
(1,'Arm',52),
(1,'Foot',54),
(1,'Tongue',55),
(1,'Arm',59),
(2,'Toe',60),
(2,'Toe',60),
(2,'Arm',61),
(3,'Tooth',75),
(3,'Tooth',76),
(3,'Knee',78)

SELECT 
    ID, 
    Age, 
    Problem, 
    COUNT(*) OVER (PARTITION BY ID, Problem, Age) as cnt,
    RANK() OVER (PARTITION BY ID, Problem ORDER BY Age) as rnk
FROM #Test1 AS t
ORDER BY  t.Age

DROP TABLE #Test1

在此解决方案中，您将获得相同的数据排名= 1（2，'Toe'，60）。 要枚举它们，请将RANK替换为ROW_NUMBER

Answer 2

我相信你想要row_number()而不是rank() ：

select 
    id 
  , Age
  , Problem
  , cnt = count(*) over (partition by id, Problem) 
  , rnk = row_number() over (partition by id, Problem order by Age) 
from t
order by id, Age, Problem

测试设置： http ： //rextester.com/DUWG50873

收益：

+----+-----+---------+-----+-----+
| id | Age | Problem | cnt | rnk |
+----+-----+---------+-----+-----+
|  1 |  50 | Arm     |   3 |   1 |
|  1 |  52 | Arm     |   3 |   2 |
|  1 |  54 | Foot    |   1 |   1 |
|  1 |  55 | Tongue  |   1 |   1 |
|  1 |  59 | Arm     |   3 |   3 |
|  2 |  60 | Toe     |   2 |   1 |
|  2 |  60 | Toe     |   2 |   2 |
|  2 |  61 | Arm     |   1 |   1 |
|  3 |  75 | Tooth   |   2 |   1 |
|  3 |  76 | Tooth   |   2 |   2 |
|  3 |  78 | Knee    |   1 |   1 |
+----+-----+---------+-----+-----+