在Firebase中更新子值

Question

我想在名为“用户”的子项中更新名为“ PhotoGallery”的子项值。

我该如何重写此代码。

func registerDatabase(id: String, url: [String: AnyObject]) {

        //Create a database reference
        let userRef = self.databaseRef.child("users").childByAutoId().child(id)

        userRef.updateChildValues(["PhotoGallery":url]) {(error, ref) in

            if error != nil{
                print("Error registering Firebase database: \(error)")

                return
            }

            print("Successfully stored in DB")
        }
    }

    func removeSpecialCharsFromString(text: String) -> String {
        let validChars: Set<Character> = Set("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLKMNOPQRSTUVWXYZ1234567890".characters)

        return String(text.characters.filter{validChars.contains($0)})
    }

Answer 1

setValue将执行此操作，因为您正在使用childByAutoId即时创建子节点。

let userChildRef = self.databaseRef.child("users").childByAutoId()
let photoRef = userChildRef.child("id").child("PhotoGallery")
photoRef.setValue(url)

结果是

users
   -Yuhusn9asijasd
      id
       PhotoGallery: "www.someurl.com"

注意，由于userChildRef现在引用了该用户的所有子项，因此我将photoRef作为单独的选项使其更具可读性

let nameRef = userChildRef.child("name")
nameRef.setValue("Gilligan")

let hatColorRef = userChildRef.child("hat")
hatColorRef.setValue("White")

let shirtColorRef = userChildRef.child("shirt")
shirtColorRef.setValue("Red")


users
   -Yuhusn9asijasd
      id:
        PhotoGallery: "www.someurl.com"
      name: "Gilligan"
      hat: "White"
      shirt: "Red"