SQL Server查询-获取多列中存在的项目

Question

我有一个简单的表格，其中包含工具的条形码ID和该工具应所属的相关房间位置。

不幸的是，我注意到有些用户为另一个房间位置输入了相同的条形码ID。

例如，我有以下两列：

barcodeNumber | RoomLocation
--------------+-------------
    123456    |    400
    654321    |    300
    875421    |    200
    654321    |    400
    999999    |    250
    878787    |    300
    777777    |    400
    999999    |    200

请注意，条形码编号“ 654321”存储在房间位置300和400，广告“ 999999”存储在房间位置200和250

如何编写SQL查询以列出重复的条形码编号和RoomLocation，而不只是重复的“计数”？

例如，我希望看到的最终结果是：

654321 | 300
654321 | 400
999999 | 200
999999 | 250

Answer 1

使用窗口函数（SQL：1999），您将得到如下结果：

with c as (
select barcodeNumber, RoomLocation,
count(*) over(partition by barcodeNumber) cnt
from t)
select barcodeNumber, RoomLocation 
from c where cnt > 1
order by 1,2

您还可以使用SQL-92语法：

select barcodeNumber, RoomLocation
from t
where barcodeNumber IN (
  select barcodeNumber from t
  group by barcodeNumber
  having count(*) > 1)
order by 1,2

Answer 2

您也可以尝试一下。 使用count(*) over (partition by barcodenumber)来确定重复值。

create table #sample (barcodenumber nvarchar(30),roomlocation int)
insert into #sample (barcodenumber,roomlocation)
select '123456',400 union all
select '654321',300 union all
select '875421',200 union all
select '654321',400 union all
select '999999',250 union all
select '878787',300 union all
select '777777',400 union all
select '999999',200

select  barcodenumber,roomlocation  from (
 select *, count(*) over (partition by barcodenumber) as rnk
 from #sample
 )t
 group by barcodenumber,roomlocation,rnk
 having rnk >1

希望这会有所帮助。

Answer 3

您是否要查找重复的条形码？

;WITH tb(barcodenumber,roomlocation)AS(
    SELECT '123456',400 UNION ALL
    SELECT '654321',300 UNION ALL
    SELECT '875421',200 UNION ALL
    SELECT '654321',400 UNION ALL
    SELECT '999999',250 UNION ALL
    SELECT '878787',300 UNION ALL
    SELECT '777777',400 UNION ALL
    SELECT '999999',200
)
SELECT * FROM (
    SELECT *,COUNT(0)OVER(PARTITION BY tb.barcodenumber) AS cnt FROM tb
) AS t WHERE t.cnt>1

barcodenumber roomlocation cnt
------------- ------------ -----------
654321        400          2
654321        300          2
999999        200          2
999999        250          2

Answer 4

这是获得结果的另一种方法：

SELECT barcodenumber, roomlocation
FROM table_name
WHERE barcodenumber IN (
        SELECT barcodenumber
        FROM table_name
        GROUP BY barcodenumber
        HAVING COUNT(DISTINCT roomlocation) > 1);
        --If you dont have duplicate rows then just use COUNT(*)

Answer 5

使用JOIN和HAVING子句：

SELECT A.barcodenumber,roomlocation
FROM #sample
JOIN 
(
  SELECT barcodenumber
  FROM #sample
  GROUP BY barcodenumber
  HAVING COUNT(*) > 1
) A ON A.barcodenumber = #sample.barcodenumber