XML返回单独的节点元素

Question

我需要以特定格式返回结果

<Applicants xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
    <Applicant>
        <Name>John Smith</Name>
        <Address>1 Smiths Close</Address>
    </Applicant>
    <Applicant>
        <Name>Peter Smith</Name>
        <Address>2 Smiths Close</Address>
    </Applicant>
</Applicants>

但是用我当前的查询

select A.Name
    , ANL.name
    , A.address AS Address
    , ANL.address AS Address
    from Agents A 
        left join AgentsNonLatin ANL 
            On A.Pn = ANL.Pn AND A.Kd = ANL.kd 
    FOR XML RAW('Applicant'), ROOT('Applicants'), ELEMENTS XSINIL

我将它们合并到单个<Applicant>节点中。

<Applicants xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
  <Applicant>
    <Name>John Smith</Name>
    <Name>Peter Smith</Name>
    <Address>1 Smiths Close</Address>
    <Address>2 Smiths Close</Address>
  </Applicant>
</Applicants>

关于需要更改以按要求的格式返回它们的任何想法？

Answer 1

在这里使用联盟

SELECT 
      A.Name
    , A.Address 
    FROM Agents A 
UNION
SELECT 
      ANL.Name
    , ANL.Address AS Address
    FROM AgentsNonLatin ANL 
FOR XML RAW('Applicant'), ROOT('Applicants'), ELEMENTS XSINIL