无法捕获异步/等待任务异常

Question

我有一种解雇方法（用于遗留目的），

BackgroundWorker.Run(() => {
          // my code here that throws an error                         
});

我不想等待BackgroundWorker.Run 。 这是我的课，

public class BackgroundWorker
{        
    public static Task Run(Action action)
    {
        return new IISBackgroundTask().DoWorkAsync(action);
    }
    class IISBackgroundTask : IRegisteredObject
    {
        public IISBackgroundTask()
        {
            HostingEnvironment.RegisterObject(this);
        }            
        void IRegisteredObject.Stop(bool immediate)
        {
            if (_task.IsCompleted || _task.IsCanceled || _task.IsFaulted || immediate)
            {
                HostingEnvironment.UnregisterObject(this);
            }
        }
        public async Task DoWorkAsync(Action action)
        {
            try
            {
                _task =  Task.Run(action);
                await _task;
            }
            catch (AggregateException ex)
            {
                // Log exceptions
                foreach (var innerEx in ex.InnerExceptions)
                {
                    Logger.Log(innerEx);
                }
            }
            catch (Exception ex)
            {
                Logger.Log(ex);
            }
        }

        private Task _task;
    }
}

我无法捕捉到异常。

更新：如果我在BackgroundWorker.Run添加一个wait，它将可以正常工作，但是我想开火并忘记。

Answer 1

目前，我已经使用

        public void DoWork(Action action)
        {
            _task = Task.Run(() => 
            {
                try
                {
                    action();
                }
                catch (AggregateException ex)
                {
                    foreach (var innerEx in ex.InnerExceptions)
                    {
                        Logger.Log(innerEx);
                    }
                }
                catch (Exception ex)
                {
                    Logger.Log(ex);
                }
            });
        }