[英]access - row_number function?
我有这个查询,它给了我postgres
所需的结果
SELECT
t.*,
ROW_NUMBER() OVER (PARTITION BY t."Internal_reference", t."Movement_date" ORDER BY t."Movement_date") AS "cnt"
FROM (SELECT
"Internal_reference",
MAX("Movement_date") AS maxtime
FROM dw."LO-D4_Movements"
GROUP BY "Internal_reference") r
INNER JOIN dw."LO-D4_Movements" t
ON t."Movement_date" = r.maxtime
AND t."Internal_reference" = r."Internal_reference"
问题是我必须在Access
上翻译上面的查询,其中分析函数不存在...
我用这个答案来构建下面的查询
SELECT
t."Internal_reference",
t.from_code,
t.to_code,
t."Movement_date",
t.shipment_number,
t."PO_number",
t."Quantity",
t."Movement_value",
t."Site",
t."Import_date",
COUNT(*) AS "cnt"
FROM (
SELECT "Internal_reference",
MAX("Movement_date") AS maxtime
FROM dw."LO-D4_Movements"
GROUP BY "Internal_reference") r
LEFT OUTER JOIN dw."LO-D4_Movements" t
ON t."Movement_date" = r.maxtime AND t."Internal_reference" = r."Internal_reference"
GROUP BY
t.from_code,
t.to_code,
t."Movement_date",
t.shipment_number,
t."PO_number",
t."Quantity",
t."Movement_value",
t."Site",
t."Import_date",
t."Internal_reference"
ORDER BY t.from_code
问题是我在cnt
列中只有1
。
我尝试通过删除internal_reference
来调整它(见下文)
SELECT
t.from_code,
t.to_code,
t."Movement_date",
t.shipment_number,
t."PO_number",
t."Quantity",
t."Movement_value",
t."Site",
t."Import_date",
COUNT(*) AS "cnt"
FROM (
SELECT "Internal_reference",
MAX("Movement_date") AS maxtime
FROM dw."LO-D4_Movements"
GROUP BY "Internal_reference") r
LEFT OUTER JOIN dw."LO-D4_Movements" t
ON t."Movement_date" = r.maxtime AND t."Internal_reference" = r."Internal_reference"
GROUP BY
t.from_code,
t.to_code,
t."Movement_date",
t.shipment_number,
t."PO_number",
t."Quantity",
t."Movement_value",
t."Site",
t."Import_date"
ORDER BY t.from_code
然而,结果更糟。 cnt
正在增长,但它给了我错误的cnt
任何帮助都非常受欢迎,因为我慢慢失去理智。
谢谢
编辑:请找到sqlfiddle
我认为Gordon-Linoff的代码接近你想要的,但有一些错字我没有改写就无法纠正,所以这是我的尝试
SELECT
t1.Internal_reference,
t1.Movement_date,
t1.PO_Number as Combination_Of_Columns_Which_Make_This_Unique,
t1.Other_columns,
Count(1) AS Cnt
FROM
([LO-D4_Movements] AS t1
INNER JOIN [LO-D4_Movements] AS t2 ON
t1.Internal_reference = t2.Internal_reference AND
t1.Movement_date = t2.Movement_date)
INNER JOIN (
SELECT
t3.Internal_reference,
MAX(t3.Movement_date) AS Maxtime
FROM
[LO-D4_Movements] AS t3
GROUP BY
t3.Internal_reference
) AS r ON
t1.Internal_reference = r.Internal_reference AND
t1.Movement_date = r.Maxtime
WHERE
t1.PO_Number>=t2.PO_Number
GROUP BY
t1.Internal_reference,
t1.Movement_date,t1.PO_Number,
t1.Other_columns
ORDER BY
t1.Internal_reference,
t1.Movement_date,
Count(1);
除了在max(movement_date)
子查询中,主表被引入两次。 一个版本是用于显示结果的版本,另一个版本用于计算记录以生成序列号。
戈登说你需要为每一行提供一个唯一的id列。 如果通过“列”表示也包含派生列,那也是如此。 此外,它只需要在“internal_reference”和“Movement_date”的任意组合中是唯一的。
我假设,也许是错误的,PO_Number就足够了。 如果没有,请与其他字段(以及一些分隔符)连接,使其成为唯一的字段。 where子句需要更新以比较“使这个唯一的列的组合”的t1和t2。
如果,没有合适的组合,我不确定如果没有VBA和/或临时表,可以像The-Gambill建议的那样完成。
据我所知,这是MS Access的真正痛苦。 一种方法是相关子查询,但每行需要一个唯一的id列:
SELECT t.*,
(SELECT COUNT(*)
FROM (SELECT "Internal_reference", MAX("Movement_date") AS maxtime
FROM dw."LO-D4_Movements"
GROUP BY "Internal_reference"
) as t2
WHERE t2."Internal_reference" AND t."Internal_reference" AND
t2."Movement_date" = t."Movement_date" AND
t2.?? <= t.??
) as cnt
FROM (SELECT "Internal_reference", MAX("Movement_date") AS maxtime
FROM dw."LO-D4_Movements"
GROUP BY "Internal_reference"
) r INNER JOIN
dw."LO-D4_Movements" t
ON t."Movement_date" = r.maxtime AND
t."Internal_reference" = r."Internal_reference";
??
用于id或创建日期或允许计数行的东西。
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