[英]A* in Javascript (with p5.js) not working
我正在为位于二维正方形阵列中的玩家编写寻路算法。 我想找到从a到b的最短路径,并有效地做到这一点。 之前我在Java(处理)中工作,而我的功能也很好。
boolean findPath(PVector down, PVector up, Square[][] board) {
PVector start = up;
PVector goal = down;
ArrayList<Square> closedSet = new ArrayList<Square>();
ArrayList<Square> openSet = new ArrayList<Square>();
HashMap<Square, Square> cameFrom = new HashMap<Square, Square>((int)Math.pow(squares, 2));
HashMap<Square, Float> gScore = new HashMap<Square, Float>((int)Math.pow(squares, 2));
HashMap<Square, Float> fScore = new HashMap<Square, Float>((int)Math.pow(squares, 2));
for (int i = 0; i<dungeon.floors.get(currentFloor).numSquares; i++) {
for (int j = 0; j<dungeon.floors.get(currentFloor).numSquares; j++) {
gScore.put(board[i][j], 1000.0);
}
}
gScore.put(board[(int)start.x][(int)start.y], 0.0);
fScore.put(board[(int)start.x][(int)start.y], heuristic(start, goal));
openSet.add(board[(int)start.x][(int)start.y]);
while (!openSet.isEmpty()) {
Square current = board[(int)start.x][(int)start.y];
float lowest = 1000;
for (Square s : openSet) {
if (fScore.get(s)<lowest) {
lowest = fScore.get(s);
current = s;
}
}
if (current.locX == goal.x && current.locY == goal.y) {
while (cameFrom.containsKey(current)) {
current = cameFrom.get(current);
}
board[(int)start.x][(int)start.y].squareType = -3;
return true;
}
openSet.remove(current);
closedSet.add(current);
//neighbors() returns an ArrayList of valid neighbors
for (Square s : current.neighbors(board)) {
if (closedSet.contains(s)) {
} else {
float tempG = gScore.get(current) + 1;
if (!openSet.contains(s)) {
openSet.add(s);
}
if (tempG < gScore.get(s)) {
cameFrom.put(s, current);
gScore.put(s, tempG);
fScore.put(s, gScore.get(s) + heuristic(new PVector(s.locX, s.locY), goal));
}
}
}
}
return false;
}
float heuristic(PVector start, PVector goal) {
return dist(start.x, start.y, goal.x, goal.y);
}
但是我正在将游戏迁移到Javascript,但是我无法确定我的代码出了什么问题。 它被卡在一个正方形上,并将其永久添加到closedSet中(数十万次)。 这是我的Javascript代码-
this.findPath = function(f, _start, _goal) {
var start = _start;
var goal = _goal;
var closedSet = [];
var openSet = [];
var squareScores = [];
var startSquare = (start.x * numSquares) + start.y;
for (var i = 0; i < numSquares; i++) {
for (var j = 0; j < numSquares; j++) {
squareScores.push(new MapSquare(dungeon.floors[f].board[i][j], 10000, 10000));
}
}
squareScores[startSquare].gScore = 0;
squareScores[startSquare].fScore = this.heuristic(start, goal);
openSet.push(squareScores[startSquare]);
while (openSet.length > 0) {
var current = squareScores[startSquare];
var lowest = 9999;
for (var s = 0; s < squareScores.length; s++) {
if (squareScores[s].fScore < lowest) {
lowest = squareScores[s].fScore;
current = squareScores[s];
}
}
if (current.square.x == goal.x && current.square.y == goal.y) {
return true;
}
openSet.splice(openSet.indexOf(current.square));
closedSet.push(current.square);
var currentNeighbors = current.square.neighbors(dungeon.floors[f].board);
for (var i = 0; i < currentNeighbors.length; i++) {
var skip = false;
for (let c of closedSet) {
if (c.x == currentNeighbors[i].x && c.y == currentNeighbors[i].y) {
skip = true;
}
}
if (skip) {
continue;
}
else {
var tempG = current.gScore + 1;
var dontAdd = false;
for (let o of openSet) {
if (o.x == currentNeighbors[i].x && o.y == currentNeighbors[i].y) {
dontAdd = true;
}
}
if (!dontAdd) {
openSet.push(currentNeighbors[i]);
}
var index = (currentNeighbors[i].x * numSquares) + currentNeighbors[i].y;
if (tempG < squareScores[index].gScore) {
//cameFrom.push(gScore[i]);
console.log("update");
squareScores[index].gScore = tempG;
squareScores[index].fScore = squareScores[index].gScore + this.heuristic(squareScores[index].square.x, squareScores[index].square.y, goal.x, goal.y);
}
}
}
}
return false;
};
//dist from player to goal
this.heuristic = function(_x1, _y1, _x2, _y2) {
return dist(_x1, _y1, _x2, _y2);
};
我的Javascript代码看起来有些不同,因为我已经尝试修复了几天,但是我无法弄清楚。 我究竟做错了什么? 如果需要澄清代码,请询问。
您将不得不调试代码。 该链接与处理中的调试有关,但是相同的思想也适用于JavaScript和P5.js。
具体来说,您需要准确确定代码的执行时间与预期的执行时间不同。
您可以通过添加做到这一点console.log()
语句要弄清楚的变量,它的功能被称为以什么顺序的价值,无论是if
语句输入,多少次的循环迭代,等等。
如果这不起作用,您还可以使用调试器逐步执行代码。 每个浏览器都带有JavaScript调试器,该调试器可让您单步执行代码并检查每个变量的值。 再次,目标是弄清楚代码什么时候做了与您期望的不同的事情。
当您将问题缩小到几行时,如果仍然不知道如何解决它,则可以创建一个MCVE来隔离问题,而无需解决所有额外的代码。 到那时,为您提供帮助将更加容易。 祝好运。
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