[英]download file java spring rest api
我想制作一个休息api控制器(弹簧启动),当用get获取请允许我下载excel文件。 目前我有这个端点:
@RequestMapping(value = "/download.xls", method = RequestMethod.GET)
public ResponseEntity Survey_Reports(@RequestParam(value = "evaluated") String evaluated){
return surveyService.getSurveysFile(evaluated);
}
最终要求这种方法:
public static ResponseEntity getDownloadResponse() {
File file2Upload = new File("Survey_Reports.xls");
Path path = Paths.get(file2Upload.getAbsolutePath());
ByteArrayResource resource = null;
try {
resource = new ByteArrayResource(Files.readAllBytes(path));
} catch (IOException e) {
logger.error("there was an error getting the file bytes ", e);
}
return ResponseEntity.ok()
.contentLength(file2Upload.length())
//this line doesnt seem to work as i set the file format in the controller request mapping
.contentType(MediaType.parseMediaType("application/vnd.ms-excel"))
.body(resource);
}
一切似乎工作半精细,因为我得到download.xls(作为映射)文件correclty,但现在我想让下载的文件有一些特定的名称,如:evaluateName.xls或userDateEndDate.xls或其他一些东西,是有没有办法编辑响应实体呢? 这样我就不必将映射命名为“download.xls”
在HttpServletResponse响应的上下文中,您可以这样做
response.setContentType("application/csv");
response.setHeader("Content-Disposition", "attachment; filename=" + csvName);
对于ResponseEntity,我假设你可以使用这样的东西:
ResponseEntity.ok().header("Content-Disposition","attachment; filename=" + csvName );
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