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[英]How to SELECT records from One table If Matching Record In Not Found In Other Table
[英]Select All Records From One Table And Matching Record From Other Table
我工作了几个小时,只是为了获得想要的SQL代码结果,但是没有运气。 我正在尝试从一个表中选择所有记录,并从另一表中选择匹配的记录。
请在此处查看实时示例。
url_id short_url campaign Clicks
1 test1 campaign1 2
2 test2 campaign2 2
上面示例中的SQL代码:
SELECT u.url_id, u.short_url, c.campaign, Count(*) AS Clicks
FROM (urls u LEFT JOIN log l ON l.url_id = u.url_id) LEFT JOIN campaign c ON u.campaign_id = c.campaign_id
WHERE (((DATE_FORMAT(l.date_time, '%Y-%m-%d')) Between '2017-03-14' And '2017-03-17'))
GROUP BY u.url_id, u.short_url, c.campaign;
我想要的结果是这样的。 包括网址表中的所有记录。
url_id short_url campaign Clicks
1 test1 campaign1 2
2 test2 campaign2 2
3 test3 campaign1 0
4 test4 0
我尝试在WHERE子句中添加l.url_id is null
,但是点击的值为1而不是零(0)
url_id short_url campaign Clicks
1 test1 campaign1 2
2 test2 campaign2 2
3 test3 campaign1 1
4 test4 1
上面示例中的SQL代码:
SELECT u.url_id, u.short_url, c.campaign, Count(*) AS Clicks
FROM (urls u LEFT JOIN log l ON l.url_id = u.url_id) LEFT JOIN campaign c ON u.campaign_id = c.campaign_id
WHERE (((DATE_FORMAT(l.date_time, '%Y-%m-%d')) Between '2017-03-14' And '2017-03-17')) or l.url_id is null
GROUP BY u.url_id, u.short_url, c.campaign;
使用COUNT(l.id)
代替COUNT(*)
。
在WHERE
子句中添加l.date_time IS NULL
。
检查http://rextester.com/YOX73980
SELECT u.url_id, u.short_url, c.campaign, Count(l.id) AS Clicks
FROM urls u
LEFT JOIN log l ON l.url_id = u.url_id
LEFT JOIN campaign c ON u.campaign_id = c.campaign_id
WHERE l.date_time IS NULL OR (DATE_FORMAT(l.date_time, '%Y-%m-%d')) Between '2017-03-14' And '2017-03-17'
GROUP BY u.url_id, u.short_url, c.campaign;
从概念上讲,仅汇总log
表可能会更容易,因为这是生成点击计数的原因,而不是其他表。 按照这些原则,我们可以尝试以下查询:
SELECT t1.url_id,
t1.short_url,
COALESCE(t2.campaign, 'NA') AS campaign,
COALESCE(t3.num_clicks, 0) AS Clicks
FROM urls t1
LEFT JOIN campaign t2
ON t1.campaign_id = t2.campaign_id
LEFT JOIN
(
SELECT url_id, COUNT(*) AS num_clicks
FROM log
WHERE DATE_FORMAT(date_time, '%Y-%m-%d') BETWEEN '2017-03-14' AND '2017-03-17'
GROUP BY url_id
) t3
ON t1.url_id = t3.url_id;
输出:
演示在这里:
SELECT u.url_id, u.short_url, c.campaign, Count(c.campaign_id) AS Clicks
FROM urls u LEFT JOIN log l ON l.url_id = u.url_id
LEFT JOIN campaign c ON u.campaign_id = c.campaign_id
AND (((DATE_FORMAT(l.date_time, '%Y-%m-%d')) Between '2017-03-14' And '2017-03-17'))
GROUP BY u.url_id, u.short_url, c.campaign;
检查演示
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