从另一个活动中注销GoogleApiClient

Question

我想使用Google帐户API构建应用。 我已经完成了使用Google教程的登录，并且效果很好，但是我尝试从其他活动中注销帐户，它也可以正常工作，但是当我评论“ onStart”就可以了，但是在类LoginActivity.java登录帐户中使用了方法“ onStart”，但是当我再次尝试登录时登录登录的帐户。 为了将googleApiClient对象传递给另一个活动，我使用了单例。 你能帮助我吗？

码：

public void onStart() {
        super.onStart();

        OptionalPendingResult<GoogleSignInResult> opr = Auth.GoogleSignInApi.silentSignIn(mGoogleApiClient);
        if (opr.isDone()) {
            Log.d(TAG, "Got cached sign-in");
            GoogleSignInResult result = opr.get();
            handleSignInResult(result);
        } else {
            showProgressDialog();
            opr.setResultCallback(new ResultCallback<GoogleSignInResult>() {
                @Override
                public void onResult(GoogleSignInResult googleSignInResult) {
                    hideProgressDialog();
                    handleSignInResult(googleSignInResult);
                }
            });
        }
    }

HomeActivity.java：

public class HomeActivity extends AppCompatActivity implements View.OnClickListener {
    private GoogleApiClient mGoogleApiClient;// = state.getmGoogleApiClient();

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_home);

        GlobalState state = ((GlobalState) getApplicationContext()); 
        mGoogleApiClient = state.getmGoogleApiClient();

        findViewById(R.id.sign_out_button).setOnClickListener(this);
    }

    private void signOut(){
        Auth.GoogleSignInApi.signOut(mGoogleApiClient).setResultCallback(
                new ResultCallback<Status>() {
                    @Override
                    public void onResult(Status status) {
                        GlobalState state = ((GlobalState) getApplicationContext()); 
                        state.setmGoogleApiClient(mGoogleApiClient);
                        Intent login = new Intent(getApplicationContext(), LoginActivity.class);
                        login.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
                        startActivity(login);
                        finish();
                    }
                });
    }



    @Override
    public void onClick(View v) {
        switch(v.getId()){
            case R.id.sign_out_button:
                signOut();
                break;
        }
    }

Answer 1

更改onStart（）与

 @Override
protected void onStart() {
    super.onStart();
    mGoogleApiClient.connect();
}

Answer 2

我通过在HomeActivity中添加onStart来解决它：

@Override
protected void onStart() {
    GoogleSignInOptions gso = new GoogleSignInOptions.Builder(GoogleSignInOptions.DEFAULT_SIGN_IN)
            .requestEmail()
            .build();
    mGoogleApiClient = new GoogleApiClient.Builder(this)
            .addApi(Auth.GOOGLE_SIGN_IN_API, gso)
            .build();
    mGoogleApiClient.connect();
    super.onStart();
}