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[英]Map multiple source fields to same type target fields with Mapstruct
[英]Mapstruct from string to nested object for multiple fields with the same type
我有Entity类的字段:
我有DTO课的字段:
如果我喜欢这样:
@Mappings({ @Mapping(source = "senderId", target = "sender.id"), @Mapping(source = "recipientId", target = "recipient.id") })
Mapstruct将生成如下代码:
public Entity toEntity(DTO) {
//...
entity.setSender( dtoToClient( dto ) );
entity.setRecipient( dtoToClient( dto ) );
//...
protected Client dtoToClient(Dto dto) {
Client client = new Client();
client.setId( dto.getRecipientId() ); // mapstruct takes recipient id for sender and recipient
return client;
}
}
Mapstruct获取发件人和收件人的收件人ID而不是收件人ID,以创建客户端收件人和发件人ID以创建客户端发件人。
所以我发现更好的方法是使用不那么优雅的表达式,据我所知:
@Mappings({
@Mapping(target = "sender", expression = "java(createClientById(dto.getSenderId()))"),
@Mapping(target = "recipient", expression = "java(createClientById(dto.getRecipientId()))")
})
你能告诉我如何映射它们吗?
在解决错误之前,您需要定义方法并使用qualifedBy
或qualifiedByName
。 有关此处的更多信息,请参阅文档。
您的映射器应如下所示:
@Mapper
public interface MyMapper {
@Mappings({
@Mapping(source = "dto", target = "sender", qualifiedByName = "sender"),
@Mapping(source = "dto", target = "recipient", qualifiedByName = "recipient")
})
Entity toEntity(Dto dto);
@Named("sender")
@Mapping(source = "senderId", target = "id")
Client toClient(Dto dto);
@Named("recipient")
@Mapping(source = "recipientId", target = "id")
Client toClientRecipient(Dto dto);
}
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