[英]Get Absolute XPath of WebElement in Java
我知道如何使用以下代码通过Javascript
获取元素的绝对 XPath:
public String getAbsoluteXPath(WebDriver driver)
{
return (String) driver.executeScript(
"function absoluteXPath(element) {"+
"var comp, comps = [];"+
"var parent = null;"+
"var xpath = '';"+
"var getPos = function(element) {"+
"var position = 1, curNode;"+
"if (element.nodeType == Node.ATTRIBUTE_NODE) {"+
"return null;"+
"}"+
"for (curNode = element.previousSibling; curNode; curNode = curNode.previousSibling){"+
"if (curNode.nodeName == element.nodeName) {"+
"++position;"+
"}"+
"}"+
"return position;"+
"};"+
"if (element instanceof Document) {"+
"return '/';"+
"}"+
"for (; element && !(element instanceof Document); element = element.nodeType == Node.ATTRIBUTE_NODE ? element.ownerElement : element.parentNode) {"+
"comp = comps[comps.length] = {};"+
"switch (element.nodeType) {"+
"case Node.TEXT_NODE:"+
"comp.name = 'text()';"+
"break;"+
"case Node.ATTRIBUTE_NODE:"+
"comp.name = '@' + element.nodeName;"+
"break;"+
"case Node.PROCESSING_INSTRUCTION_NODE:"+
"comp.name = 'processing-instruction()';"+
"break;"+
"case Node.COMMENT_NODE:"+
"comp.name = 'comment()';"+
"break;"+
"case Node.ELEMENT_NODE:"+
"comp.name = element.nodeName;"+
"break;"+
"}"+
"comp.position = getPos(element);"+
"}"+
"for (var i = comps.length - 1; i >= 0; i--) {"+
"comp = comps[i];"+
"xpath += '/' + comp.name.toLowerCase();"+
"if (comp.position !== null) {"+
"xpath += '[' + comp.position + ']';"+
"}"+
"}"+
"return xpath;"+
"} return absoluteXPath(arguments[0]);", this.element);
}
但是,如果例如我可以访问HTML source
,我不确定如何直接通过 Java 执行此操作。
怎么可能呢?
Google.com 上徽标的绝对 XPath 将是:
html/body/div[1]/div[6]/span/center/div[1]/img
而 Google Logo 的相对 XPath 是: .//*[@id='hplogo']
给定元素 + HTML,如何获取 Web 元素的绝对 XPath?
谢谢
希望下面的逻辑有帮助
function absolutePath(element) {
if (element.tagName.toLowerCase() == 'html')
return '/html[1]';
if (element === document.body)
return '/html[1]/body[1]';
var ix = 0;
var siblings = element.parentNode.childNodes;
for (var i = 0; i < siblings.length; i++) {
var sibling = siblings[i];
if (sibling === element)
return absolutePath(element.parentNode) + '/' + element.tagName.toLowerCase() + '[' + (ix + 1) + ']';
if (sibling.nodeType === 1 && sibling.tagName.toLowerCase() === element.tagName.toLowerCase())
ix++;
}
}
它是一个更简化的版本
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