如何在C＃中使用XElement生成对象列表的xml

Question

我正在尝试使用XElement将对象列表转换为xml。 我的代码如下

 var employees = new List<Employee>();

 employees.Add(new Employee("1", " Ali","",1000));
 employees.Add(new Employee("2", "Billy","",1001));

 var xml = new XElement("root");
 xml.Add(new XElement("Employees"));

 foreach (var employee in employees)
  {
    xml.Add(new XElement("employee", employee.Name));
  };

我想要这样的输出

<root>
 <Employees>
   <employee>Ali</employee>
   <employee>Billy</employee>
 </Employees>
</root>

但是我得到的输出是

 <root>
 <Employees/>
   <employee>Ali</employee>
   <employee>Billy</employee>
</root>

我尝试将Employees对象移动到如下所示的循环内，但这无济于事

 foreach (var employee in employees)
  {
    xml.Add(new XElement("Employees", new XElement("employee", employee.Name)));

  };

Answer 1

在循环中，应该在employee元素而不是root上调用Add() ：

 var employees = new List<Employee>();

 employees.Add(new Employee("1", " Ali","",1000));
 employees.Add(new Employee("2", "Billy","",1001));

 var xml = new XElement("root");
 var employeesElement = new XElement("Employees");

 foreach (var employee in employees)
 {
    employeesElement.Add(new XElement("employee", employee.Name));
 }
 xml.Add(employeesElement);

Answer 2

XElement构造函数可以处理IEnumerable因此您可以在创建父Employees时立即添加employee元素。 实际上，整个XML可以一次创建：

var xml = new XElement("root",
    new XElement("Employees",
        employees.Select(e => new XElement("employee", e.Name))
    )
);