在匿名回调PHP中访问实例变量

Question

让我们假设我有一个类，我必须从回调内部设置实例变量。

class A{
   protected $user;

   public __construct(){
      /* Some function here which accept callback */
      StoreData(['name'=>'Stackoverflow'],function($response){
           //how to assign value to $user here???
      });
   }
}

Answer 1

这样的事情怎么样？

class A{
    protected $user;

    public function  __construct(){
        $this->user = 'hehexd';
    }

    public function  getFunction(){
        $temp = $this->user; // or a reference
        $rval = function($response) use ($temp){
            echo $temp;
        };

        return $rval;
    }
}

$a = new A();
$func = $a->getFunction();
$func('response');
exit;

Answer 2

您可以将整个对象分配给变量并将其注入use()从而修改对象（可能这就是您的意思？） ：

<?php
class bug
    {
        protected $user;

        public  function test()
            {
                $thisObj    =   $this;
                goo('test',function() use ($thisObj) {
                    $thisObj->user  =   'foooooooo';
                });

                echo $this->user;
            }
    }

function goo($val,$callback)
    {
        $callback();
    }

$bug    =   new bug();
$bug->test();

你会得到：

foooooooo

Answer 3

$message = 'hello';

// No "use"
$example = function () {
    var_dump($message);
};
$example();

// Inherit $message
$example = function () use ($message) {
    var_dump($message);
};
$example();

http://php.net/manual/en/functions.anonymous.php