内部联接和回声解决方案

Question

我有三个表的内部联接：

    $result=mysql_query("SELECT singleimageupload.codrif AS codrif,
       singleimageupload.imagesname AS bigimage,
       uploads.imagesname AS multipleimage,
       uploads.description AS multipledescription,
       exposition.name,
       exposition.author,
       exposition.description,
       exposition.misure,
       exposition.date,
       exposition.status
  FROM exposition
 INNER JOIN singleimageupload ON singleimageupload.codrif = exposition.codrif
 INNER JOIN uploads ON uploads.codrif = exposition.codrif
 WHERE singleimageupload.firstimage = 'first' AND exposition.codrif = 'A002'
 ORDER BY exposition.codrif");

我得到这个结果：

在这种情况下，我拥有的每个上传路径都有一个结果。

我的目标是得到这样的东西：

因此，我想合并其Cod Rif的所有上载路径（在此示例中为A002）。

这是我的完整代码：

  <?php



include('guestconfig/config.php');



$result=mysql_query("SELECT singleimageupload.codrif AS codrif,
       singleimageupload.imagesname AS bigimage,
       uploads.imagesname AS multipleimage,
       uploads.description AS multipledescription,
       exposition.name,
       exposition.author,
       exposition.description,
       exposition.misure,
       exposition.date,
       exposition.status
  FROM exposition
 INNER JOIN singleimageupload ON singleimageupload.codrif = exposition.codrif
 INNER JOIN uploads ON uploads.codrif = exposition.codrif
 WHERE singleimageupload.firstimage = 'first' AND exposition.codrif = 'A002'
 ORDER BY exposition.codrif");




while ($row = mysql_fetch_assoc($result)) {


?>
<table border="0">

<tr>
<td> <?php echo $row['codrif']?> </td>
</tr>
<tr>

<td> <?php echo $row['bigimage']?> </td>
</tr>
<tr>

<td> <?php echo $row['name']?> </td>
</tr>
<tr>

<td> <?php echo $row['author']?> </td>
</tr>
<tr>

<td> <?php echo $row['multipledescription']?> </td>

</tr>
<hr>
</table>

<?php } ?>

我不知道我是否解释清楚，希望如此

Answer 1

尝试使用group_concat（uploads.description）并按singleimageupload.codrif分组