数据自动插入数据库中的PHP

Question

我有一个问题，就是用户在我的评论表单中写入成功时会插入用户，但是当我刷新页面时它将再次插入最后一个评论，我在此链接中阅读了解决方案， 如何停止将数据自动插入php中的数据库

但对我不起作用，这是我的代码，感谢您的帮助

viewhospital.php文件包含include comments.php文件-请看代码底部-

 <?php include ('header.php'); if(!isset($_GET['hospital_id'])){ echo '<div class="alert alert-danger" role="alert"><b>You should choose hospital before opening this page!</b></div>'; include ('footer.php'); die(); } include ('setting.php'); $sql = 'select * from hospital where hid = '. $_GET['hospital_id']; $result = $conn->query($sql) or die(mysql_error($conn)); $hospital = null; if ($result->num_rows > 0) { $hospital = $result->fetch_assoc(); } else { die('Could not find hospital!'); } $sql = 'select * from doctor where hospital_id = '. $_GET['hospital_id']; $doctor_result = $conn->query($sql) or die(mysql_error($conn)); $conn->close(); ?> <div class="row"> <div class="col-md-6"> <p class="text-center"> <img src="<?php echo $hospital['image']; ?>" class="img-thumbnail" style="height: 400px;"> </p> </div> <div class="col-md-6"> <p class="text-center"> <img class="img-thumbnail" src="https://maps.googleapis.com/maps/api/staticmap?center=<?php echo $hospital['location']; ?>&zoom=13&size=400x400&maptype=roadmap&markers=color:blue%7Clabel:S%7C<?php echo $hospital['location']; ?>&key=AIzaSyD59nHXpZgqZwjJvsAcPe2CYcIEWoaQ9yY" style="height: 400px;"> </p> </div> </div> <div class="row"> <div class="col-md-12"> <h1 class="page-header"> <?php echo $hospital['name']; ?> </h1> <p> <?php echo $hospital['description']; ?> </p> <p> Address: <?php echo $hospital['address']; ?> </p> <p> Phone: <?php echo $hospital['phone']; ?> </p> <p> <a href="<?php echo $hospital['link1']; ?>">Go To Hospital</a> </p> <p> <a href="<?php echo $hospital['link2']; ?>">Online Appointment</a> </p> </div> </div> <!--<div class="row"> <div class="col-md-12 text-center"> <div class="btn-group" role="group" aria-label="..."> <a type="button" class="btn btn-info">Edit</a> <a type="button" class="btn btn-danger">Remove</a> <a type="button" class="btn btn-primary" href="doctor_form.php?hospital_id=<?php echo $hospital['hid']; ?>">Add Doctor</a> </div> </div> </div>--> <div class="row"> <div class="col-md-12"> <table class="table table-striped"> <caption>Doctors:</caption> <thead> <tr> <th>#</th> <th>Name</th> <th>Field</th> <th></th> </tr> </thead> <tbody> <?php if ($doctor_result->num_rows > 0) { while($row = $doctor_result->fetch_assoc()) { ?> <tr> <th scope="row"> <?php echo $row['did'];?> </th> <td> <?php echo $row['name'];?> </td> <td> <?php echo $row['field'];?> </td> <td><a href="view_hospital.php?doctor_id=<?php echo $row['did']; ?>" class="btn btn-success pull-right">View</a></td> </tr> <?php } }else{ ?> <tr> <th scope="row"></th> <td>No doctors found</td> <td></td> </tr> <?php } ?> </tbody> </table> </div> </div> <?php include ('comments.php'); include ('footer.php'); ?> 

comments.php文件

 <?PHP # comments PHP code date_default_timezone_set('Asia/Riyadh'); function setComments (){ if (isset($_POST['submitComments'])){ include('setting.php'); //$uid = $_POST['uid']; $date = $_POST['date']; $message = $_POST['message']; $sql = "INSERT INTO comments ( date, message) VALUE ( '$date', '$message')"; $result = mysqli_query($conn,$sql); } } function getComments (){ if (isset($_POST['submitComments'])){ include('setting.php'); $sql = "SELECT * FROM comments"; $result = mysqli_query($conn,$sql); while ($row = $result->fetch_assoc()){ echo "<div class='comments-box'>"; echo $row['date']."<br>"; echo nl2br($row['message'])."<br><br>"; echo "</div>"; } } } echo " <form action='".setComments ()."' method='POST'> <input type='hidden' name='uid' value=''> <input type='hidden' name='date' value='".date('Ymd H:i:s')."'> <textarea name='message' class='form-control' rows='3'></textarea> <br> <button type='submit' name='submitComments' class='btn btn-primary'>Comments</button> </form> <br><br> "; getComments (); ?> 

Answer 1

在浏览器中刷新时，您会再次发送上一个请求。 该请求是表单的POST。 因此，用户（浏览器）正在告诉代码插入另一个注释。

通常，这是通过发布表单后重定向而不是重新显示表单来处理的。 移动所有逻辑（仅用于），将新内容插入其自己的PHP文件（类似于addComment.php ），并将表单发布到该文件。 然后在该文件中确保没有实际输出，除非出现问题时可能显示一条错误消息？），然后重定向回页面：

header("Location: viewhospital.php");

这将指示浏览器在响应中对viewhospital.php进行新的GET请求。 因此，如果用户重新加载浏览器，那么他们要做的就是重复该GET请求。