如何在2个php文件之间传递变量

Question

我有两个php文件，用于对活动目录用户进行身份验证，我想从中获取属性url ，如果该函数返回true，则该值$data从authenticate.php传递到login.php到header("Location: *URL*"); ，如何才能做到这一点？

authenticate.php：

<?php
  // Initialize session
  session_start();

  function authenticate($user, $password) {
  if(empty($user) || empty($password)) return false;

  // Active Directory server
  $ldap_host = "CRAMSDCR01V.cloud4rain.local";

  // connect to active directory
  $ldap = ldap_connect($ldap_host);

  $ldap_dn="OU=by-style,DC=cloud4rain,DC=local";

  // verify user and password
  if($bind = @ldap_bind($ldap, $user, $password)) 
  {
    $result = ldap_search($ldap,$ldap_dn, "(cn=*)") or die ("Error in search query: ".ldap_error($ldap));
    $data = ldap_get_entries($ldap, $result);
    echo $data["url"];
    return true;    
  } 
  else 
  {
    // invalid name or password
    return false;
  }
 }
?>

login.php：

<?php
include("authenticate.php");

// check to see if user is logging out
if(isset($_GET['out'])) {
// destroy session
session_unset();
$_SESSION = array();
unset($_SESSION['user'],$_SESSION['access']);
session_destroy();
}

// check to see if login form has been submitted
if(isset($_POST['btn-login'])){
// run information through authenticator
if(authenticate($_POST['userLogin'],$_POST['userPassword']))
{
  // authentication passed
  header("Location: authenticate.php?$data");
  die();
 } else {
  // authentication failed
  $error = "Login failed: Incorrect user name, password, or rights<br /-->";
}
}

// output logout success
if(isset($_GET['out'])) echo "Logout successful";
?>

Answer 1

login.php

<?php
include("authenticate.php");

从本质上讲，这就像将authenticate.php的内容粘贴到login.php中一样 ，尽管从技术上讲它是2个文件，但它的作用就像是一个文件-但是$data是在authenticate()函数中定义的，因此仅在该函数范围内 。

在authenticate.php中 -从函数返回数据

// verify user and password
if($bind = @ldap_bind($ldap, $user, $password)) 
{
    $result = ldap_search($ldap,$ldap_dn, "(cn=*)") or die ("Error in search query: ".ldap_error($ldap));
    $data = ldap_get_entries($ldap, $result);
    // echo $data["url"]; // I assume this is just for debugging...

    // return $data from the function which should be "truthy"
    return $data;
} 
else 
{
    // invalid name or password
    return false;
}

在login.php中 -评估authenticate()函数的返回值-由于PHP松散地键入，因此该函数返回的任何（非空）字符串都可以被评估为“真实” -您从该函数获得的唯一其他返回值是false ...

// run information through authenticator
if($authData = authenticate($_POST['userLogin'],$_POST['userPassword']))
{
  // authentication passed
  // renamed the variable $authData just for clarity
  header("Location: authenticate.php?$authData"); 
  die();
 } 

 else {
  // authentication failed
  $error = "Login failed: Incorrect user name, password, or rights<br />";
}

Answer 2

不知道为什么会有$_SESSION = array(); 在login.php中，但是如果要将$ data从一个php传递到另一个php，则只需在会话中将其设置为

$_SESSION['data'] = $data;

ang在其他文件中使用它

$data = $_SESSION['data'];