[英]Data not displayed when fetched from a MySQL database using PHP
我是stackoverflow的新手,所以对不起,如果我做错了。
问题:我已经用HTML在PHP中创建了一个函数,但是我不知道为什么我的数据不显示。
这是代码:
<?php
<!-- here is `require blabla.php` -->
function showName(){
$sql="SELECT company_name FROM company WHERE 1";
$result=mysqli_query($connection, $sql);
if (!$result) {
die('Invalid query: ' . mysqli_error());
}
$row=mysqli_fetch_array($result);
$var=$row['company_name'];
echo $var;
}
?>
<!-- HTML Code -->
<td><b>Company Name: </b></td>
<td><input type="text" class="form-control" value="<?php showName(); ?>" id="name" required name="name"></td>
- 编辑 -
myConnection.php
<?php
$connection = mysqli_connect("localhost", "root", "", "pos");
if (!$connection) {
die("Database connection failed: " . mysqli_connect_error());
}
$db_select = mysqli_select_db($connection, "pos");
if (!$db_select) {
die("Database selection failed: " . mysqli_connect_error());
}
?>
您忘记添加myConnection.php
。
<?php
function showName(){
require 'myConnection.php';
$sql="SELECT company_name FROM company WHERE 1";
$result=mysqli_query($connection, $sql);
if (!$result) {
die('Invalid query: ' . mysqli_error());
}
$row=mysqli_fetch_array($result);
$var=$row['company_name'];
echo $var;
}
?>
<!-- HTML Code -->
<td><b>Company Name: </b></td>
<td><input type="text" class="form-control" value="<?php showName(); ?>" id="name" required name="name"></td>
maincode.php
<?php
require_once 'myconnection.php' ;
function showName(){
global $connection;
$sql="SELECT company_name FROM company WHERE 1";
$result=mysqli_query($connection, $sql);
if (!$result) {
die('Invalid query: ' . mysqli_error());
}
$row=mysqli_fetch_array($result);
$var=$row['company_name'];
echo $var;
}
?>
<td><b>Company Name: </b></td>
<td><input type="text" class="form-control" value="<?php showName(); ?>"
id="name" required name="name"></td>
myconnection.php
<?php
$connection = mysqli_connect("localhost", "root","");
if (!$connection) {
die("Database connection failed: " . mysqli_connect_error());
}
$db_select = mysqli_select_db($connection, "pos");
if (!$db_select) {
die("Database selection failed: " . mysqli_connect_error());
}
?>
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