[英]JPQL query that returns entities involving a many to many relationship
我需要一个返回的JPQL查询:
我尝试过类似的东西:
SELECT t
FROM Tweet t
WHERE t.author.id = :userId
OR t.author.id IN (
SELECT u.followedUsers
FROM User u
WHERE u.id = :userId
)
只是发现子查询语法错误 。 此外,我不能像在SQL中那样调用关系表User_User,因为JPA不会识别它
用户
@Entity
public class User {
@Id
@GeneratedValue
private long id
@ManyToMany(mappedBy = "followedUsers")
private Set<User> followers;
@ManyToMany
private Set<User> followedUsers;
}
鸣叫
@Entity
public class Tweet {
@Id
@GeneratedValue
private long id;
@ManyToOne
private User author;
}
鉴于此查询
OR t.author.id IN (
SELECT u.followedUsers
FROM User u
WHERE u.id = :userId
)
您正试图在User
对象列表中找到Integer (t.author.id)
! 我认为这应该有效:
SELECT t
FROM Tweet t
WHERE t.author.id = :userId
OR t.author MEMBER OF (
SELECT u.followedUsers
FROM User u
WHERE u.id = :userId
)
编辑
... MEMBER OF (subquery)...
是不允许的,但将子查询合并到其父级中会解决此问题。
SELECT DISTINCT(t)
FROM Tweet t, User u
WHERE t.author.id = :userId
OR (t.author MEMBER OF u.followedUsers AND u.id = :userId)
我习惯让JPQL查询更类似于SQL查询。 所以,我的建议是:
SELECT t FROM Tweet t
JOIN t.author a
WHERE a.id = :idUser
OR a.id IN (SELECT followedUser.id
FROM User u
JOIN u.followedUsers followedUser
WHERE u.id = :idUser)
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