![](/img/trans.png)
[英]How to copy paste data based on some criterias from one workbook to another(specific cells) using VBA?
[英]VBA copying data from one workbook to specific cells in another, based on criteria
我有 2 个工作簿,需要将第 26 列中为“是”的行中的数据复制到目标工作簿中的特定单元格。 我目前将以下代码附加到源表上的按钮上:
Sub exportData()
Dim LastRow As Integer
Dim i As Integer
Dim erow As Integer
LastRow = ActiveSheet.Range("A" & rows.Count).End(xlUp).Row
For i = 2 To LastRow
If Cells(i, 26).Value = "Yes" Then
Range(Cells(i, 1), Cells(i, 26)).Select
Selection.Copy
Workbooks.Open Filename:=ThisWorkbook.Path & "\GI New Starter Tracker 2017edit.xlsx"
Worksheets("Main").Select
erow = ActiveSheet.Cells(rows.Count, 1).End(xlUp).Offset(1, 0).Row
ActiveSheet.Cells(erow, 1).Select
ActiveSheet.Paste
'ActiveSheet.Range("$A$1:$AB$3000").RemoveDuplicates Columns:=2, Header:=xlYes
ActiveWorkbook.Save
ActiveWorkbook.Close
Application.CutCopyMode = False
End If
Next i
End Sub
代码工作正常,但是它复制了整行,但我只需要复制某些信息,如“名字”、“姓氏”、“出生日期”。 目标工作簿没有完全相同的标题,所以我需要能够指定哪一列。
我一直在拉我的头发,非常感谢任何帮助。
谢谢 :)
这应该这样做。 您需要将列号更改为工作簿中的相应列....
Sub exportData()
Dim LastRow As Integer
Dim i As Integer
Dim erow As Integer
Dim wbk As Workbook
Dim SourceSheet As Worksheet
Dim DestSheet As Worksheet
Dim firstName, surName, DoB
Set SourceSheet = ActiveSheet
LastRow = SourceSheet.Range("A" & Rows.Count).End(xlUp).Row
Set wbk = Workbooks.Open(ThisWorkbook.Path & "\GI New Starter Tracker 2017edit.xlsx")
Set DestSheet = wbk.Sheets("Main")
For i = 2 To LastRow
If SourceSheet.Cells(i, 26).Value = "Yes" Then
'change the column numbers to the relevant number
firstName = SourceSheet.Cells(i, 23).Value
surName = SourceSheet.Cells(i, 24).Value
DoB = SourceSheet.Cells(i, 25).Value
erow = DestSheet.Cells(DestSheet.Rows.Count, 1).End(xlUp).Offset(1, 0).Row
'change the column numbers to the relevant number
DestSheet.Cells(erow, 10).Value = firstName
DestSheet.Cells(erow, 11).Value = surName
DestSheet.Cells(erow, 12).Value = DoB
End If
Next i
wbk.Save
wbk.Close
End Sub
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.