MySQL和PHP选择*查询不起作用

Question

我的数据库中有一个名为sales的表。 每行在“联邦”列中都有一个值。 因此，我想在此代码中将所有联邦收集到一个数组中，但是它不起作用，我也不知道为什么……请帮助！ 谢谢！

  <?php
              $db = mysqli_connect("server", "usr", "pw", "db");

              $FederalRes = $db->query("SELECT * FROM `sales` WHERE `state` = 'Österreich'"); //gets every row with the state = 'Österreich'

              $federals = array(); // empty array to collect federals

              while ($row = $FederalRes->fetch_object()) {
                if (!in_array($row->federal, $federals)) { // check if federal is already in array
                  array_push($federals, $row->federal); // adds federal to array
                }
              }

              sort($federals); // sorts the array alphabetically

              foreach ($federals as $key => $value): ?>
                <li><?php echo $value ?></li>
              <?php endforeach; ?>

Answer 1

您尝试使用LIKE语句而不是= 。

请尝试以下代码：

<?php
  $db = mysqli_connect("server", "usr", "pw", "db");

  $FederalRes = $db->query("SELECT * FROM `sales` WHERE `state` LIKE 'Österreich'"); //gets every row with the state = 'Österreich'

  $federals = array(); // empty array to collect federals

  while ($row = $FederalRes->fetch_object()) {
    if (!in_array($row->federal, $federals)) { // check if federal is already in array
      array_push($federals, $row->federal); // adds federal to array
    }
  }

  sort($federals); // sorts the array alphabetically

  foreach ($federals as $key => $value): ?>
    <li><?php echo $value ?></li>
  <?php endforeach; ?>

Answer 2

<?php
try{
$conn = new PDO('mysql:host=localhost;dbname=test;charset=utf8', 'root',     '');
}

catch(Exception $e){
die('Erreur : '.$e->getMessage());
}

$answer= $conn->query("SELECT * FROM sales WHERE state LIKE 'Österreich' ORDER BY state ASC"); //sort it alphabetically here ;)


while ($data = $answer->fetch()){
    echo $data['federal'] . '<br />';
}
$reponse->closeCursor();

?>