使用php和mysql更新

Question

我已经在线学习了使用CRUD的教程。 但是，我来了Update部分，我在GET函数和fetch_row上遇到了一些问题。

未定义的变量：第69行的C：\\ xampp \\ htdocs \\ Website \\ editsuppliers.php中的fetched_row是一条错误消息，下一条是未定义的索引：editsuppliers

这是我到目前为止所拥有的。

<?php 
include_once 'connect.php' ;
if(isset($_GET['editsuppliers']))
{
 $sql_query="SELECT * FROM suppliers WHERE SuppliersID=".$_GET['editsuppliers'];
 $result_set=mysql_query($sql_query);
 $fetched_row=mysql_fetch_array($result_set);
}
if(isset($_POST['btn-update']))
{
 // variables for input data
$SupplierID = $_POST['SupplierID'];
 $SupplierName = $_POST['SupplierName'];
 $Address = $_POST['Address'];
 $EmailAddress = $_POST['EmailAddress'];
 $PhoneNumber = $_POST['PhoneNumber'];
  // variables for input data

 // sql query for update data into database
 $sql_query = "UPDATE suppliers SET SupplierID='$SupplierID',SupplierNamee='$SupplierName',Address='$Address',EmailAddress='$EmailAddress',PhoneNumber'$PhoneNumber' WHERE SupplierID=".$_GET['editsuppliers'];
 // sql query for update data into database

 // sql query execution function
 if(mysql_query($sql_query))
 {
  ?>
  <script type="text/javascript">
  alert('Data Updated Successfully');
  window.location.href='suppliers.php';
  </script>
  <?php
 }
 else
 {
  ?>
  <script type="text/javascript">
  alert('error occured while updating data');
  </script>
  <?php
 }
 // sql query execution function
}
if(isset($_POST['btn-cancel']))
{
 header("Location: suppliers.php");
}
?>

<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Edit Suppliers</title>
<link rel="stylesheet" href="style.css" type="text/css" />
</head>
<body>
<center>

<div id="header">
 <div id="content">
    <label</label>
    </div>
</div>

<div id="body">
 <div id="content">
    <form method="post">
    <table align="center">
    <tr>
    <td><input type="text" name="SupplierID" placeholder="Supplier ID" value="<?php echo $fetched_row['SupplierID']; ?>" required /></td>
    </tr>
    <tr>
    <td><input type="text" name="SupplierName" placeholder="Supplier Name" value="<?php echo $fetched_row['SupplierName']; ?>" required /></td>
    </tr>
    <tr>
    <td><input type="text" name="Address" placeholder="Address" value="<?php echo $fetched_row['Address']; ?>" required /></td>
    </tr>
    <tr>
    <td><input type="text" name="EmailAddress" placeholder="Email Address" value="<?php echo $fetched_row['EmailAddress']; ?>" required /></td>
    </tr>
    <tr>
    <td><input type="text" name="PhoneNumber" placeholder="Phone Number" value="<?php echo $fetched_row['PhoneNumber']; ?>" required /></td>
    </tr>
    <tr>
    <td>
    <button type="submit" name="btn-update"><strong>UPDATE</strong></button>
    <button type="submit" name="btn-cancel"><strong>Cancel</strong></button>
    </td>
    </tr>
    </table>
    </form>
    </div>
</div>

</center>
</body>
</html>

Answer 1

根据您的声明，确保您在url中传递editsuppliers 。

请更详细地解释错误。

使用php和mysql更新

问题描述

1 个解决方案

解决方案1
0 2017-04-15 17:16:56

使用php和mysql更新

问题描述

1 个解决方案

解决方案1 0 2017-04-15 17:16:56

解决方案1
0 2017-04-15 17:16:56