如何使用Rest API在PHP脚本中设置用于Salesforce登录的用户名和密码

Question

我正在尝试登录我的Salesforce帐户并检索一些数据。 到目前为止，我已经能够通过在Salesforce登录页面上提供用户名和密码来登录到Salesforce，然后重定向到我有一些echo语句的数据页面。 我想知道如何在PHP本身中设置用户名和密码，并成功登录Salesforce。我使用了Salesforce提供的本文档， 与PHP的Force.com REST API进行交互

请帮忙。

以下是我的config.php

<?php

    ini_set('display_errors',1);
    error_reporting(E_ALL ^ E_WARNING); 

    define("CLIENT_ID", "xxx");
    define("CLIENT_SECRET", "xxx");
    define("REDIRECT_URI", "https://xxxx/oauth_callback.php");
    define("LOGIN_URI", "https://login.salesforce.com");

    define("USERNAME","xxxx@xxx.com");
    define("PASSWORD","*******");
    define("SECURITY_TOKEN","xxxx");

?>

以下是我的oauth.php

<?php
require_once 'config.php';

$auth_url = LOGIN_URI
        . "/services/oauth2/authorize?response_type=code&client_id="
        . CLIENT_ID . "&redirect_uri=" . urlencode(REDIRECT_URI);

header('Location: ' . $auth_url);
?>

以下是我的oauth_callback.php

<?php
require_once 'config.php';

session_start();

$token_url = LOGIN_URI . "/services/oauth2/token";

$code = $_GET['code'];

if (!isset($code) || $code == "") {
    die("Error - code parameter missing from request!");
}

$params = "code=" . $code
    . "&grant_type=authorization_code"
    . "&client_id=" . CLIENT_ID
    . "&client_secret=" . CLIENT_SECRET
    . "&username=" . USERNAME
    . "&password=" . PASSWORD
    . "&redirect_uri=" . urlencode(REDIRECT_URI);

$curl = curl_init($token_url);
curl_setopt($curl, CURLOPT_HEADER, false);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_POST, true);
curl_setopt($curl, CURLOPT_POSTFIELDS, $params);
curl_setopt($curl, CURLOPT_CAINFO, dirname(__FILE__) . '/cacert.pem');
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, true);


$json_response = curl_exec($curl);

$status = curl_getinfo($curl, CURLINFO_HTTP_CODE);

if ( $status != 200 ) {
    die("Error: call to token URL $token_url failed with status $status, response $json_response curl_error " . curl_error($curl) . " curl_errno " . curl_errno($curl));
}

curl_close($curl);

$response = json_decode($json_response, true);

$access_token = $response['access_token'];
$instance_url = $response['instance_url'];

if (!isset($access_token) || $access_token == "") {
    die("Error - access token missing from response!");
}

if (!isset($instance_url) || $instance_url == "") {
    die("Error - instance URL missing from response!");
}

$_SESSION['access_token'] = $access_token;
$_SESSION['instance_url'] = $instance_url;

header( 'Location: demo_rest.php' ) ;
?>

以下是我的demo_rest.php （显示输出）

$query = "SELECT Id FROM test__c limit 3";

$url = "$instance_url/services/data/v20.0/query?q=" . urlencode($query);

$curl = curl_init($url);
curl_setopt($curl, CURLOPT_HEADER, false);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_HTTPHEADER,
        array("Authorization: OAuth $access_token"));
curl_setopt($curl, CURLOPT_CAINFO, dirname(__FILE__) . '/cacert.pem');
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, true);

$json_response = curl_exec($curl);
curl_close($curl);

$response = json_decode($json_response, true);

$total_size = $response['totalSize'];

echo "$total_size record(s) returned<br/><br/>";

echo "<br/>";

print_r($json_response);

Answer 1

问题是您无法在demo_rest.php文件中获取变量$ instance_id和$ access_token的值。

将您的demo_rest.php文件的代码替换为下面的代码。

<?php
session_start();

$access_token = $_SESSION['access_token'];
$instance_url = $_SESSION['instance_url'];

$query = "SELECT Id FROM test__c limit 3";

$url = "$instance_url/services/data/v20.0/query?q=" . urlencode($query);

$curl = curl_init($url);
curl_setopt($curl, CURLOPT_HEADER, false);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_HTTPHEADER,
        array("Authorization: OAuth $access_token"));
curl_setopt($curl, CURLOPT_CAINFO, dirname(__FILE__) . '/cacert.pem');
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, true);

$json_response = curl_exec($curl);
curl_close($curl);

$response = json_decode($json_response, true);

$total_size = $response['totalSize'];

echo "$total_size record(s) returned<br/><br/>";

echo "<br/>";

print_r($json_response);
?>

如果它不起作用，请给我留言。