![](/img/trans.png)
[英]Unable to push all expected data to an array from collection using foreach loop in PHP
[英]PHP - Push data to array in foreach loop
我想实现以下数组格式:
{
"success": true,
"results": [
{
"name" : "Choice 1",
"value" : "value1",
"text" : "Choice 1"
},
{
"name" : "Choice 2",
"value" : "value2",
"text" : "Choice 2"
}
]
}
但是,我使用PHP和foreach循环,从我的数据库返回一些值:
//Search for clients in our database.
$stmt = $dbh->prepare("SELECT * FROM customers");
$stmt->execute();
$showAll = $stmt->fetchAll();
然后我有我的第一部分数组,以及我的foreach循环:
$data = array(
"success" => false,
"results" => array()
);
foreach ($showAll as $client) {
$data_array[] =
array(
'name' => $client['name'],
'value' => $client['name'],
'text' => $client['name']
);
}
以上仅输出:
[
{
"name":"Choice 1",
"value":"value 1",
"text":"Choice 1"
},
{
"name":"Choice 2",
"value":"value2",
"text":"Choice 2"
}
]
所以它缺少原始数组的顶部 - 但我想循环遍历每个数据库导致"results": [ ... ]
尝试这个
$data = array(
"success" => false,
"results" => array()
);
foreach ($showAll as $client) {
$data['results'][] = array(
'name' => $client['name'],
'value' => $client['name'],
'text' => $client['name']
);
}
$data['success'] = true; // if you want to update `status` as well
echo json_encode($data);
创建$data_array
数组后,只需在我的帖子中添加几行。
在此处尝试此代码段 (带示例输入)
ini_set('display_errors', 1);
foreach ($showAll as $client)
{
$data_array[] = array(
'name' => $client['name'],
'value' => $client['name'],
'text' => $client['name']
);
}
// add these lines to your code.
$result=array();
$result["success"]=true;
$result["results"]=$data_array;
echo json_encode($result);
尝试这个,因为你在键“结果”上的$ data_array中有一个数组,所以你应该使用“结果”作为键,然后尝试推送该数组中的数据
foreach ($showAll as $client) {
$data_array["results"][] =
array(
'name' => $client['name'],
'value' => $client['name'],
'text' => $client['name']
);
}
您只需使用json_encode并将其推送到结果数组即可
$data = array(
"success" => false,
"results" => array()
);
$result = [
[
"name" => "Choice 1",
"value" => "value 1",
"text" => "Choice 1"
],
[
"name" => "Choice 2",
"value" => "value2",
"text" => "Choice 2"
]
];
$data['results'] = json_encode($result);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.