SQL - 多个条件where子句相同的列

Question

我有一个看起来像这样的数据集

Subject_ID   Diagnosis_ID  
001          299
001          288
001          233
001          299
002          299
002          233
003          238
004          299
004          233

我想创建一个新的表格，其中包含诊断代码为299和233的患者。

到目前为止尝试的代码已经

Select *
  From mytable 
 where diagnosis_id = 299 AND diagnosis_id=233

这没用 -

我也试过了

Select *
  From mytable 
 where diagnosis_id = 299 
INTERSECT
Select *
From mytable 
where diagnosis_id= 233

这也没有用。

Answer 1

select  Subject_ID from (
     Select Distinct Subject_ID, Diagnosis_ID
       From
       Table_1
       Where Diagnosis_ID=299 or Diagnosis_ID=288
)
Group By Subject_ID
Having count(Subject_ID)>=2

Answer 2

你可以使用IN（）....

  SELECT * FROM TABLE
  WHERE diagnosis_id IN(233, 299);

Answer 3

想group by和having ：

Select patient_id
From mytable
where diagnosis_id in (299, 233)
group by patient_id
having count(*) = 2;

注意：如果您的表可以有重复项，则使用count(distinct diagnosis_id) = 2 。

Answer 4

检查一下： -

Select subject_id 
from
(
Select distinct subject_id, diagnosis_id
from
mytable
where diagnosis_id in ('299','233')
) a
group by subject_id
having count(*)=2

谢谢：-）

Answer 5

很简单，你可以使用这个：

Select *
  From mytable 
 where (diagnosis_id = 299 or diagnosis_id=233)