[英]MySQL PHP ID in one table and not another
| Fixture_ID | League_ID | Home_Team | Away_Team
| 1 | 1 | 1 | 2
| 2 | 1 | 2 | 3
| 3 | 1 | 3 | 1
| Result_ID | Fixture_ID | Home_Goals | Away_Goals
| 1 | 1 | 2 | 0
| Team_ID | Team_Name |
| 1 | Team A
| 2 | Team B
| 3 | Team C
我如何加入表格以仅显示未输入结果的灯具,但在显示灯具时(在下拉列表中)输出实际的团队名称(Team A v Team B)?
以下代码适用于输出所有灯具:
echo '<td> <select name ="fixture_id">';
// TRY TO SHOW FIXTURES WITH NO RESULTS
$stmt = $pdo->prepare('SELECT f.*, t1.Team_Name AS Home, t2.Team_Name AS Away
FROM Fixture f
INNER JOIN Team t1 ON f.Home_Team = t1.Team_ID
INNER JOIN Team t2 ON f.Away_Team = t2.Team_ID');
$stmt->execute();
foreach ($stmt as $row) {
echo '<option>' . $row['Home'] . ' v ' . $row['Away'] . '</option>';
}
?>
您的SQL应如下所示:
SELECT f.*, t1.Team_Name AS Home, t2.Team_Name AS Away
FROM Fixture f
INNER JOIN Team t1 ON f.Home_Team = t1.Team_ID
INNER JOIN Team t2 ON f.Away_Team = t2.Team_ID
LEFT JOIN Result r ON f.Fixture_ID = r.Fixture_ID
WHERE r.id IS NULL;
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