[英]Warning: Illegal string offset error
我正在尝试用php创建一个简单的搜索引擎,如果用户输入关键字,他们可以按事件名称或位置进行搜索。 然后按日期顺序显示结果。 大部分已从另一个站点获取,但我正在尝试对其进行转换。
有人可以简单地向新手解释以下错误,以及如何纠正错误?
/home/ubuntu/workspace/test/test.php:49:array(5){'eventID'=>字符串(1)“ 1”'eventName'=>字符串(8)“令人兴奋”'eventLocation'=>字符串(7)“体育场”'开始'=>字符串(10)“ 2017-04-01”'过期'=>字符串(10)“ 2017-04-30”}警告:/ home中的字符串偏移'eventName'不合法第50行上的/ubuntu/workspace/test/test.php调用堆栈:0.0003 238624 1. {main}()/home/ubuntu/workspace/test/test.php:0 1
<?php
session_start();
//include files
include 'header/header.php';
include 'nav/navigation.php';
include 'init.php';
$expires = strtotime($_POST["expires"]);
$expires = date('Y-m-d', $expires);
$events = "";
$find = $_POST['find'];
$field = $_POST['field'];
$searching = true;
if(isset($_POST["submit"])) {
if(!empty($_POST["events"])) {
$searching = false;
}
//This is only displayed if the user submitted the form
if($searching == true)
{
echo "<h2>Results</h2><p>";
//If the user did not enter a search term, they receive an error
if ($find == "")
{
echo "<p>You forgot to enter a search term";
exit;
}
// Otherwise we connect to the database
//$result = mysqli_query($connection,$query) or exit ("Error in query:
$query. ".mysqli_error($connection));
// We preform a bit of filtering
$find = strtoupper($find);
$find = strip_tags($find);
$find = trim ($find);
//Now we search for our search term, in the field the user specified
$mysqli = new mysqli('localhost', 'root', '', 'c3470438');
$query = "SELECT * FROM events WHERE upper(eventLocation)
LIKE'%STADIUM%'";
$result = $mysqli->query($query);
//Temporarily echo $query for debugging purposes
//echo "$query";
//exit;
//And display the results
$row = $result->fetch_array(MYSQLI_ASSOC);
echo "<br>";
foreach($row as $item) {
var_dump($row);
echo $item['eventName'];
exit();
}
exit;
//This counts the number or results. If there aren't any, it gives an
explanation
$anymatches=mysql_num_rows($data);
if ($anymatches == 0) {
echo "Sorry, but we can not find an entry to match your query<br>
<br>";
}
//And reminds the user what they searched for
echo "<b>Searched For:</b> " .$find;
}
}
?>
<fieldset>
<legend><h2>Events</h2></legend>
<form name="search" method="post" action="<?=$PHP_SELF?>">
<tr> <th> <td>
<fieldset>
<legend>Find all events</legend>
<input type="radio" name="events" <?php if (isset($events) &&
$events=="all") echo "checked";?>value="all"> Display all events
</fieldset>
<fieldset>
<legend>Find events by date</legend>
<input type="date" name="date" min="<?php echo date("Y-m-d");?>"
max="2025-01-01" value="<?php echo date("Y-m-d");?>">
</fieldset>
<fieldset>
<legend>Find events by keywords</legend>
<input type="hidden" placeholder='Search by keyword'name="searching"
value="yes" />
Search for: <input type="text" name="find" /> in
<Select NAME="field">
<Option VALUE="eventName">Event Name</option>
<Option VALUE="eventLocation">Event Location</option>
</Select>
<input type="hidden" name="searching" value="yes" />
<input type="submit" name="submit" value="submit" />
</form>
</fieldset>
<button name="submit" value="submit" type="submit" class="button
expanded">Submit </button>
<button type="reset" value="Clear"class="button expanded">
Clear</button>
</fieldset>
</select> </td></tr>
<?php
//include files
include 'footer/footer.php';
?>
<script src="js/vendor/jquery.js"></script>
<script src="js/foundation.min.js"></script>
<script>
</script>
</body>
$result->fetch_array(MYSQLI_ASSOC)
返回一行,但是您正在使用它,就好像它返回了所有行一样。 因此,您的foreach会迭代该行中的每个字段,而不是每一行,因此您正在尝试访问字符串的数组键。
像这样使用一段时间:
while($row = $result->fetch_array(MYSQLI_ASSOC)){
echo $row['eventName'];
}
另外,您使用的不是mysqli的mysql_num_rows
。 而是使用$result->num_rows
。
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