为树中的任何给定节点递归生成层次结构？

Question

此CTE提取SuiteID和ParentSuiteID的层次结构作为下面的结果集。 我想传递作为各自级别的父级的SuiteID和所有SuiteID 。

WITH HIERARCHY AS
( select T1.SuiteID,T1.Title,T1.ParentSuiteID, 0 Level 
  FROM tbl_Suite(nolock) T1
  Where T1.ParentSuiteID = 0 AND T1.PlanID = '404'
  UNION ALL
  select T2.SuiteID,T2.Title,T2.ParentSuiteID,Level+1 
  from tbl_Suite(nolock) AS T2
  INNER JOIN HIERARCHY AS H ON T2.ParentSuiteID = H.SuiteID
)

SELECT * 
FROM HIERARCHY

+---------+------------------------+---------------+-------+
    | SuiteID |         Title          | ParentSuiteID | Level |
    +---------+------------------------+---------------+-------+
    |   10664 | root                   |             0 |     0 |
    |   10681 | Prod Test Environment  |         10664 |     1 |
    |   11097 | Dev Test Environment   |         10664 |     1 |
    |   11155 | Training Environment   |         10664 |     1 |
    |   11156 | Production Environment |         10664 |     1 |
    |   11100 | Bridge PMS             |         11097 |     2 |
    |   11126 | Bridge PTS             |         11097 |     2 |
    |   11139 | Client 360             |         11097 |     2 |
    |   11140 | Contact Manager        |         11097 |     2 |
    |   11145 | Revenue DashBoard      |         11097 |     2 |
    |   11141 | Finance flow           |         11140 |     3 |
    |   11142 | Premium Finance flow   |         11140 |     3 |
    |   11143 | Client Contacts        |         11140 |     3 |
    |   11127 | Direct Bill            |         11126 |     3 |
    +---------+------------------------+---------------+-------+

我想编写一个查询，通过时提供以下结果集（SuiteID = 11100）：

SuiteID Title                      ParentSuiteID    Level 
10664   root                        0                  0
11097   Dev Test Environment        10664              1
11100   Bridge PMS                  11097              2

Answer 1

Declare @Table table (SuiteID  int,Title varchar(50),ParentSuiteID int)
Insert into @Table values 
(10664 ,'root                   ',    0),
(10681 ,'Prod Test Environment  ',10664 ),
(11097 ,'Dev Test Environment   ',10664 ),
(11155 ,'Training Environment   ',10664 ),
(11156 ,'Production Environment ',10664 ),
(11100 ,'Bridge PMS'             ,11097 )


Declare @Fetch int = 11100   

;with cteHB as (
      Select SuiteID 
            ,ParentSuiteID
            ,Lvl=1
            ,Title 
      From   @Table 
      Where  SuiteID =@Fetch
      Union  All
      Select R.SuiteID 
            ,R.ParentSuiteID
            ,P.Lvl+1
            ,R.Title 
      From   @Table R
      Join   cteHB P on P.ParentSuiteID = R.SuiteID )
Select Lvl = Row_Number() over (Order By Lvl Desc) -1
      ,SuiteID 
      ,ParentSuiteID
      ,Title
From cteHB
Order By 1

退货

Lvl SuiteID ParentSuiteID   Title
0   10664   0               root                   
1   11097   10664           Dev Test Environment   
2   11100   11097           Bridge PMS