获取记录，其中一个列的值在具有相同列名的记录之间的范围内

Question

如下表

+------+-----+------+----------+-----------+
| city | day | hour | car_name | car_count |
+------+-----+------+----------+-----------+
|    1 |  12 |   00 | corolla  |         8 |
|    1 |  12 |   00 | city     |         9 |
|    1 |  12 |   00 | amaze    |         3 |
|    1 |  13 |   00 | corolla  |        17 |
|    1 |  13 |   00 | city     |         2 |
|    1 |  13 |   00 | amaze    |         8 |
|    1 |  14 |   00 | corolla  |         3 |
|    1 |  14 |   00 | amaze    |         1 |
+------+-----+------+----------+-----------+

需要找出city, day, hour ，其中car_count所有car_name s是> = 3和<= 10

预期结果

| city | day | hour |  
+------+-----+------+ 
|    1 |  12 |   00 |

Answer 1

使用group by并having 。

select city,day,hour
from tablename
group by city,day,hour
having sum(case when car_count>=3 and car_count<=10 then 1 else 0 end) = count(*)

Answer 2

select city, day, hour
from t
group by 1, 2, 3
having bool_and(car_count >= 3)

Answer 3

您可以通过城市，日和小时的有 之条件（你的病情）=次数 群 （你的病情）
因此，基本上，我们正在为满足条件“ 10> = car_count> = 3”的每一行创建一个标志。 现在，我们对所有标志求和并同时对其进行计数，如果计数和总和相等，则意味着您的条件“ 10> = car_count> = 3”对于所有针对城市，日和小时的汽车而言为真

create table want as
select city,day,hour from have
group by city,day,hour
having sum(car_count>=3 and car_count<=10)=count(car_count>=3 and car_count<=10);

如有任何疑问，请让我知道。