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[英]@Caching method called from spring boot test [annotated with @Transactional] not working
[英]Spring boot test @Transactional not saving
我正在尝试使用 Spring Boot Test 进行简单的集成测试,以测试 e2e 用例。 我的测试不起作用,因为我无法使存储库保存数据,我认为我的 spring 上下文有问题......
这是我的实体:
@Entity
@Getter
@Setter
@NoArgsConstructor
@AllArgsConstructor
public class Person {
@Id
private int id;
private String name;
}
这是个人资料库:
@Repository
public interface PersonRepository extends JpaRepository<Person, Integer> {
}
人员服务:
@Service
public class PersonService {
@Autowired
private PersonRepository repository;
public Person createPerson(int id,String name) {
return repository.save(new Person(id, name));
}
public List<Person> getPersons() {
return repository.findAll();
}
}
个人控制器:
@RequestMapping
@RestController
public class PersonController {
@Autowired
private PersonService personService;
@RequestMapping("/persons")
public List<Person> getPersons() {
return personService.getPersons();
}
}
主要应用类:
@SpringBootApplication
public class BootIntegrationTestApplication {
public static void main(String[] args) {
SpringApplication.run(BootIntegrationTestApplication.class, args);
}
}
application.properties 文件:
spring.datasource.url= jdbc:mysql://localhost:3306/test
spring.datasource.username=root
spring.datasource.password=password
spring.jpa.hibernate.ddl-auto=create
spring.jpa.show-sql=true
和测试:
@RunWith(SpringRunner.class)
@SpringBootTest(webEnvironment = SpringBootTest.WebEnvironment.RANDOM_PORT)
public class BootIntegrationTestApplicationTests {
@Autowired
private PersonService personService;
@Autowired
private TestRestTemplate restTemplate;
@Test
@Transactional
public void contextLoads() {
Person person = personService.createPerson(1, "person1");
Assert.assertNotNull(person);
ResponseEntity<Person[]> persons = restTemplate.getForEntity("/persons", Person[].class);
}
}
测试不起作用,因为服务没有保存 Person 实体....提前致谢
@RunWith(SpringJUnit4ClassRunner.class)
@SpringApplicationConfiguration(classes = Application.class)
public class SmokeTest {
@Autowired
UserController userController;
@Autowired
UserDao userDAO;
@Rollback(false) // This is key to avoid rollback.
@Test
public void contextLoads() throws Exception {
System.out.println("Hiren");
System.out.println("started");
userDAO.save(new User("tyx", "x@x.com"));
}
}
参考@Rollback(false)
是避免回滚的关键。
感谢 M. Deinum,我想我明白了,所以最好的办法是将测试逻辑分成两个测试,第一个将只测试服务(因此这个可以是事务性的),第二个是控制器:
测试 1:
@Test
@Transactional
public void testServiceSaveAndRead() {
personService.createPerson(1, "person1");
Assert.assertTrue(personService.getPersons().size() == 1);
}
测试 2:
@MockBean
private PersonService personService;
@Before
public void setUp() {
//mock the service
given(personService.getPersons())
.willReturn(Collections.singletonList(new Person(1, "p1")));
}
@Test
public void testController() {
ResponseEntity<Person[]> persons = restTemplate.getForEntity("/persons", Person[].class);
Assert.assertTrue(persons.getBody()!=null && persons.getBody().length == 1);
}
用于保存实体的 Spring 需要事务。 但是在事务被提交之前,更改从另一个事务中是不可见的。
最简单的方法是在提交事务后调用控制器
@Test
@Transactional
public void contextLoads() {
Person person = personService.createPerson(1, "person1");
Assert.assertNotNull(person);
TransactionSynchronizationManager.registerSynchronization(new TransactionSynchronizationAdapter() {
@Override
public void afterCommit() {
ResponseEntity<Person[]> persons = restTemplate.getForEntity("/persons", Person[].class);
}
});
}
对于每个进行数据库事务的@Test
函数,如果你想永久保留更改,那么你可以使用@Rollback(false)
@Rollback(false)
@Test
public void createPerson() throws Exception {
int databaseSizeBeforeCreate = personRepository.findAll().size();
// Create the Person
restPersonMockMvc.perform(post("/api/people")
.contentType(TestUtil.APPLICATION_JSON_UTF8)
.content(TestUtil.convertObjectToJsonBytes(person)))
.andExpect(status().isCreated());
// Validate the Person in the database
List<Person> personList = personRepository.findAll();
assertThat(personList).hasSize(databaseSizeBeforeCreate + 1);
Person testPerson = personList.get(personList.size() - 1);
assertThat(testPerson.getFirstName()).isEqualTo(DEFAULT_FIRST_NAME);
assertThat(testPerson.getLastName()).isEqualTo(DEFAULT_LAST_NAME);
assertThat(testPerson.getAge()).isEqualTo(DEFAULT_AGE);
assertThat(testPerson.getCity()).isEqualTo(DEFAULT_CITY);
}
我使用 jHipster 生成的 SpringBoot 项目对其进行了测试:
不要使用@Rollback(false)
。 单元测试不应生成数据。
JPA FlushMode 是AUTO
(默认 - 查询发生时刷新 INSERT/UPDATE/DELETE SQL)/ COMMIT
。
只需查询工作实体强制刷新,或使用 EntityManager 强制刷新
@Test
public void testCreate(){
InvoiceRange range = service.createInvoiceRange(1, InvoiceRangeCreate.builder()
.form("01GTKT0/010")
.serial("NV/18E")
.effectiveDate(LocalDate.now())
.rangeFrom(1L)
.rangeTo(1000L)
.build(), new byte[] {1,2,3,4,5});
service.findByCriteria(1, "01GTKT0/010", "NV/18E"); // force flush
// em.flush(); // another way is using entityManager for force flush
}
请注意测试执行的顺序,带有@Commit 或@Rollback(false) 注释的测试必须首先执行: https ://www.baeldung.com/junit-5-test-order
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