[英]Check two lists for order equality after sorting elements of one list
[英]Sorting lists with one instance
您好,我试图将我从数据库中获得的两个排序列表传递给我的jsp页面,
@RequestMapping(value = "/sortDate", method= RequestMethod.GET)
public void sortedLists(Model model, HttpSession session){
List<Song> songsByDate;
try {
songsByDate = SongDAO.getInstance().getAllSongs();
Collections.sort(songsByDate, new UploadTimeComparator());
session.setAttribute("songs", songsByDate);
/////////////////////////////////
List<Song> songsByLikes;
try {
songsByLikes = SongDAO.getInstance().getAllSongs();
Collections.sort(songsByLikes, new LikesComparator());
session.setAttribute("songs2", songsByLikes);
}}}
但是问题是由于我使用getInstance(),Songs和Songs2是按Likes排序的相同List,如何解决这个问题?
您需要将每个“所有歌曲”列表复制到新的数组列表,然后可以继续进行排序。
所以:
List<Song> songsByDate = new ArrayList<>( SongDAO.getInstance().getAllSongs() );
Collections.sort( songsByDate, new UploadTimeComparator() );
List<Song> songsByLikes = new ArrayList<>( SongDAO.getInstance().getAllSongs() );
Collections.sort( songsByLikes, new LikesComparator() );
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