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[英]How to call another javascript function within a javascript function after previous codes have been executed?
[英]How to call a function multiple times 1 second after the same function has been executed in a previous call? (javascript)
我的问题是如何在一秒后调用函数“changeArray”? 我希望第一个“changeArray”在1秒后被调用,下一个在2秒后被调用,依此类推。 因此,在执行上一个函数后,应该在1秒后调用每个函数。
var array = [ [0,0,0], [0,0,0], [0,0,0] ]; function changeArray(i,j) { array[i][j] +=1; } changeArray(1,1); //after 1 second changeArray(1,1); //after 2 seconds changeArray(0,0); //after 3 seconds changeArray(0,0); //after 4 seconds console.log(array);
如果没有关于如何确定要传递给changeArray
参数的changeArray
,可以尝试这样做:
function addInterval(func, i) {
window.setTimeout(function() {
func();
}, 1000 * i);
}
addInterval(() => changeArray(1, 1), 1);
addInterval(() => changeArray(1, 1), 2);
addInterval(() => changeArray(0, 0), 3);
addInterval(() => changeArray(0, 0), 4);
您可以使用Window setTimeout
方法。 如果您需要更好的语法或在循环中使用它,您可以在下面定义辅助方法:
defer = function(method, seconds, args) {
var fn = function() {
return method.apply(null, args);
}
return setTimeout(fn, seconds * 1000);
}
并使用它:
defer(changeArray, 1, [1, 1]);
defer(changeArray, 2, [1, 1]);
defer(changeArray, 3, [0, 0]);
defer(changeArray, 4, [0, 0]);
或者在for循环中:
var count = 1;
for(var i = 0; i < array.length; i++) {
var row = array[i];
for(var j = 0; j < row.length; j++) {
defer(changeArray, count, i, j);
count++;
}
}
setTimeout(() => changeArray(1,1), 1000); //after 1 second
var counter=0
setInterval(function(){
++window.counter;
var a, b;
if (window.counter== /*however many seconds */ ) {
a=//what ever you want for the time passed
b=//what ever you want for the time passed
}
// add more if statements like that for different times
changeArray(a, b);
}, 1000)
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