如何显示另一个类的输入（java）

Question

我正在开发有关创建学生记录系统的硬件，但我不知道为什么我的代码无法显示所有输入。 你们能给我一些解决这个问题的建议吗？ 我的预期输出是：0：名字，姓氏，身份证，学生编号，分数

这是我的代码：

import java.util.Scanner;`
    public class semifinal{
        static String[][] records = new String[50][50];
        static int num = 0;
        public static void main(String args[]){
            Scanner kb = new Scanner(System.in);
            System.out.println("Welcome to the Student record management system!");
            System.out.println();
            int i, n = 0;
            while(true){
                System.out.println("enter 'input' for inputting student's records"); 
                System.out.println("enter 'update' for updating the student's records"); 
                System.out.println("enter 'search' for searching the student's records"); 
                System.out.println("enter 'display' for displaying all students according to the final exam scores.");
            String word = kb.nextLine();
            if(word.equals("input")){
                System.out.println("Input student["+num+"]:");
                System.out.println("input <first name> ");
                String firstname = kb.nextLine();
                System.out.println("input <last name> ");
                String lastname = kb.nextLine();
                System.out.println("input <ID> ");
                String id = kb.nextLine();
                System.out.println("input <Student Number>");
                String num = kb.nextLine();
                insert(firstname, lastname, id, num);
            }else if(word.equals("update")){
                System.out.println("Enter the student number to update the student records"); 
                String num = kb.nextLine(); 
                System.out.println("Update the final exam score:"); 
                String score = kb.nextLine(); 
                update(num, score);
            }else if(word.equals("search")){
                System.out.println("Enter the student number to search the student records");
                String number = kb.nextLine();
                String[] input = search(number);
                System.out.println();
                System.out.println(input[0]+" "+input[1]+" "+input[2]+" "+input[3]+" "+input[4]+" ");           

            }else if(word.equals("display")){ 
                Display();

            }else{
                System.out.println();
                System.out.println("Please enter a valid input again!");

            }
        }
    }
    public static void insert(String firstname, String lastname, String id, String num){
        for(int i = 0; i<records.length; i++){
        records[i][0] = firstname;
        records[i][1] = lastname;
        records[i][2] = id;
        records[i][3] = num;
        i++;
    }
    }
    public static void update(String num, String score){
        for(int i = 0; i<records.length; i++){
        records[i][4] = score;
        String[] update = search(num);
        update[4] = score;
        }
    }
    public static String[] search(String number){
        for(int i = 0; i<records.length; i++){
            if(number.equals(records[i][3])){
                 return records[i];
                 }
            }
            return null;
        }

   public static void Display(){
                sort();
                for(int i = 0; i<num; i++){
                    System.out.println(num+" "+records[i][0]

+" "+records[i][1]+" "+records[i][2]+" "+records[i][3]+" "+records[i][4]);
            }
        }

        public static void sort(){
            int[] sort = new int[num];
            for(int i = 0; i<num; i++){
                sort[i] = Integer.parseInt(records[i][4]);
            }
            for(int i = 0; i<num-1; i++){
                for(int j = i+1; j<num; j++){
                    if(sort[j]<sort[i]){
                        int temp = sort[j];
                        String[] x = records[j];
                        records[j] = records[i];
                        records[i] = x;
                        sort[j] = sort[i];
                        sort[i] = temp;
                    }
                }
            }
        }

我的代码有什么问题吗？ 我不知道如何解决它。

Answer 1

您正在隐藏num变量

您已将其设置为字段

int num = 0;

但是在您的代码中，您也有

String num = kb.nextLine(); 

可能应该用

num = Integer.valueof(kb.nextLine());

Answer 2

该代码存在许多逻辑错误。 我在评论中强调了其中一些。 我已经修复了部分问题，您可以继续工作。

public static void main(String[] args) {
        Scanner kb = new Scanner(System.in);
        System.out.println("Welcome to the Student record management system!");
        System.out.println();
        int i, n = 0;
        while(true){
            System.out.println("enter 'input' for inputting student's records");
            System.out.println("enter 'update' for updating the student's records");
            System.out.println("enter 'search' for searching the student's records");
            System.out.println("enter 'display' for displaying all students according to the final exam scores.");
            String word = kb.nextLine();
            if(word.equals("input")){
                System.out.println("Input student["+ ++num +"]:");
                System.out.println("input <first name> ");
                String firstname = kb.nextLine();
                System.out.println("input <last name> ");
                String lastname = kb.nextLine();
                System.out.println("input <ID> ");
                String id = kb.nextLine();
                System.out.println("input <Student Number>");
                String studNum = kb.nextLine();
                insert(firstname, lastname, id, studNum);
            }else if(word.equals("update")){
                System.out.println("Enter the student number to update the student records");
                String num = kb.nextLine();
                System.out.println("Update the final exam score:");
                String score = kb.nextLine();
                update(num, score);
            }else if(word.equals("search")){
                System.out.println("Enter the student number to search the student records");
                String number = kb.nextLine();
                String[] input = search(number);
                System.out.println();
                System.out.println(input[0]+" "+input[1]+" "+input[2]+" "+input[3]+" "+input[4]+" ");

            }else if(word.equals("display")){
                Display();

            }else{
                System.out.println();
                System.out.println("Please enter a valid input again!");

            }
        }
    }

插入时无需循环。

public static void insert(String firstname, String lastname, String id, String studNum){
        int index = num -1;
        records[index][0] = firstname;
        records[index][1] = lastname;
        records[index][2] = id;
        records[index][3] = studNum;
    }

无需在显示中打印索引4（注释排序，因为没有时间修复该索引）。

public static void Display(){
        //sort();
        for(int i = 0; i<num; i++){
            System.out.println(num+" "+records[i][0]

                    +" "+records[i][1]+" "+records[i][2]+" "+records[i][3]);
        }
    }

现在它将至少打印记录。