通过Jquery查找相同类型的下一个元素

Question

大家好，请检查以下html。

    <div class="mainDiv2">
        <a href="home00.html" >home00</a>
        <a href="home0.html" >home0</a><br /><br />
        <h1>Employee List</h1>
        <a href="home.html" >home</a><br /><br />
        <a href="home2.html" >home2</a>
        <a href="home3.html" >home3</a>
        <h1>Employee List2</h1>
        <a href="home4.html">home4</a>
        <a href="home5.html">home5</a>
        <h1>Employee List3</h1>
        <a href="home6.html">home6</a>
        <a href="home7.html">home7</a>
        <a href="home8.html">home8</a>
        <a href="home9.html" class="active">home9</a>

        <p>
            {!PageTitle}
        </p>
    </div>
    <div>
        <a class="btn btn-default" id="prevRec" href="#">Pre</a>
        <a class="btn btn-default" id="nextRec" href="#">Next</a>
    </div>

我想要的是那个。 如果在href上实现了.active类，那么我想获取相同类型的上一个和下一个元素href值。 在当前的html中，它将返回

上一篇：home8.html下一篇：空

在以下情况下

    <div class="mainDiv2">
        <a href="home00.html" >home00</a>
        <a href="home0.html" >home0</a><br /><br />
        <h1>Employee List</h1>
        <a href="home.html" >home</a><br /><br />
        <a href="home2.html" >home2</a>
        <a href="home3.html" >home3</a>
        <h1>Employee List2</h1>
        <a href="home4.html">home4</a>
        <a href="home5.html">home5</a>
        <h1>Employee List3</h1>
        <a href="home6.html" class="active">home6</a>
        <a href="home7.html">home7</a>
        <a href="home8.html">home8</a>
        <a href="home9.html" >home9</a>

        <p>
            {!PageTitle}
        </p>
    </div>

它将返回

上一页：home5.html下一页：home7.html

注意：请记住，a标签之间有h1标签。.为了让大家知道我已经回答了这个问题..但我想要其他解决方案。 我认为这不是正确的解决方案。

如果这是我的答案：

 $(document).ready(function () {
        var currActive = $('div[class="mainDiv2"]').find('a.active');

        if ($(currActive).nextAll('a').length > 0) {
            var nextHref = $(currActive).nextAll('a').attr("href")
            $("#nextRec").attr("href", nextHref);
        }
        else
            $("#nextRec").attr("href", 'http://www.google.com').text("Home");

        //--------------

        if ($(currActive).prevAll('a').length > 0) {
            var preHref = $(currActive).prevAll('a').attr("href")
            $("#prevRec").attr("href", preHref);
        }
        else
            $("#prevRec").attr("href", 'http://www.google.com').text("Home");
    });

谢谢..

Answer 1

为此，您可以使用prevAll()和nextAll()来获取所需的元素，即使它们之间存在h1 。 尝试这个：

 var $active = $('a.active'); var prev = $active.prevAll('a').first().attr('href'); var next = $active.nextAll('a').first().attr('href'); console.log(prev); console.log(next); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div class="mainDiv2"> <a href="home00.html">home00</a> <a href="home0.html">home0</a><br /><br /> <h1>Employee List</h1> <a href="home.html">home</a><br /><br /> <a href="home2.html">home2</a> <a href="home3.html">home3</a> <h1>Employee List2</h1> <a href="home4.html">home4</a> <a href="home5.html">home5</a> <h1>Employee List3</h1> <a href="home6.html" class="active">home6</a> <a href="home7.html">home7</a> <a href="home8.html">home8</a> <a href="home9.html">home9</a> <p> {!PageTitle} </p> </div> 

Answer 2

您可以通过消除不属于链接的任何元素来尝试使用prev / next这样的操作，这将捕获多个活动类（如果存在）：

 $('.mainDiv2').clone().find('*').remove('*:not("a")').end().find('.active').each(function(){ var next = $(this).next('a').attr('href'); var prev = $(this).prev('a').attr('href'); console.log(prev== undefined?'google.com':prev,next == undefined?'google.com':next); }) 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div class="mainDiv2"> <a href="home00.html">home00</a> <a href="home0.html">home0</a><br /><br /> <h1>Employee List</h1> <a href="home.html">home</a><br /><br /> <a href="home2.html">home2</a> <a href="home3.html">home3</a> <h1>Employee List2</h1> <a href="home4.html">home4</a> <a href="home5.html">home5</a> <h1>Employee List3</h1> <a href="home6.html" class="active">home6</a> <a href="home7.html">home7</a> <a href="home8.html">home8</a> <a href="home9.html">home9</a> <a href="home10.html" class="active">home6</a> <p> {!PageTitle} </p> </div>