[英]How to make this programm to count the odd and even numbers in an array?(eclipse)
谢谢大家的回答,没想到会这么快就得到答案。
好的,因此在最后阶段的这段代码中,这意味着要计算您确定的数组长度中有多少个奇数和偶数。
例如,如果键入10,它将在0-999的时间间隔之间打印出10个随机数,然后将奇数和偶数分开
在最后一个阶段,它是要计算有多少个奇数和偶数,例如“ 10个数字中有4个是偶数而6个是奇数”
现在,在最后阶段,它只是随机输出数字,而不计算有多少个奇数和偶数。 我不知道该如何解决。
我没有关于它的想法,所以希望这里有人可以使其正常工作。
import java.util.Scanner;
public class Uppgift4 {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int length;
while (true)
{
System.out.print(" \n\nHow many numbers do you want in the intervall 0-999?(turn off with -1 or 1000):");
length = scan.nextInt();
if (length>999)
{
System.out.print("\nValue outside intervall restart programm");
break;
}
if (length<0)
{
System.out.print("\nValue outside intervall restart programm");
break;
}
System.out.println("\n Here are the random numbers:");
int [] ar1 = new int[length];
for(int i = 0; i < length; i++) {
ar1[i] = (int)(Math.random() * 1000);
{
System.out.print(" "+ar1[i]);
}
}
System.out.println(" \n");
System.out.println(" Here are the numbers divided between even and odd numbers:");
System.out.print(" ");
for(int i = 0 ; i < length ; i++)
{
if(ar1[i] % 2 == 0)
{
System.out.print(ar1[i]+" ");
}
}
System.out.print("- ");
for(int i = 0 ; i < length ; i++)
{
if(ar1[i] % 2 != 0)
{
System.out.print(ar1[i]+" ");
}
}
System.out.println(" \n");
System.out.print(" Of the above numbers "+ length + " so ");
System.out.print("where ");
for(int evennumbers = 1 ; evennumbers < length ; evennumbers++)
{
if(ar1[evennumbers] % 2 == 0)
{
System.out.print(evennumbers+" ");
}
}
System.out.print(" of the numbers even and odd numbers were ");
for(int oddnumbers = 1 ; oddnumbers < length ; oddnumbers++)
{
if(ar1[oddnumbers] % 2 != 0)
{
System.out.print(oddnumbers+" ");
}
}
}
}
您需要计算偶数和奇数:
int even = 0;
int odd = 0;
// Loop through the final array
for(int i = 0 ; i < length ; i++)
{
if(ar1[i] % 2 == 0)
{
even++;
} else {
odd++;
}
}
更简单:
for(int i = 0 ; i < length ; i++)
{
odd += (ar1[i] % 2)
}
even = length - odd;
只需使两个全局变量计数奇数和偶数,然后将它们置于要检查奇数和偶数的条件即可。 码
为什么不只使用按位AND并删除这些条件,如下所示:
int odd = 0;
int even = 0;
for(int i=0;i<length;i++){
odd+=ar1[i]&1;
even+=((ar1[i]+1)&1);
}
您可以使用这种方式,非常简单
public static void main(String []args){
Integer[] arr = new Integer[] { 1,2,3,4,5};
int oddCount =0; int evenCount=0;
for ( int i=0; i< arr.length ;i++){
if( ( arr[i] % 2) == 0 )
evenCount++;
if( arr[i] % 2 != 0 )
oddCount++;
}
System.out.println( "oddCount in Array :" + oddCount + " EvenCount in Array : " + evenCount);
}
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