[英]C# Parse XML into Object with child elements
我试图将XML文件读入C#对象。 XML包含多个子元素。 使用以下代码,我可以毫无问题地访问所有顶部字段(版本,实时,pageid等),但是当我尝试访问子节点值时,会收到一个
Object reference not set to an instance of an object.
我认为这表明XMLSerializer无法将节点与我的对象匹配。 我尝试了不同的对象类型,例如数组上的List字段,但似乎仍然得到相同的结果,因此我不确定实现此目的的最佳方法是什么?
向我指出正确方向的任何帮助将不胜感激。
XML
<?xml version="1.0" encoding="utf-8"?>
<LiveModelStruct xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<version>1</version>
<live>true</live>
<pageid>1</pageid>
<data>test data</data>
<giveawayactive>false</giveawayactive>
<giveawayserial>00000000</giveawayserial>
<templates>
<template>
<id>1</id>
<title>Template 1</title>
<type>Opener</type>
</template>
<template>
<id>2</id>
<title>Template 2</title>
<type>Song</type>
</template>
</templates>
</LiveModelStruct>
宾语
[XmlRoot(ElementName = "LiveModelStruct")]
public class LiveModelStruct
{
[XmlElement(ElementName = "version")]
public string version { get; set; }
[XmlElement(ElementName = "live")]
public string live { get; set; }
[XmlElement(ElementName = "pageid")]
public string pageid { get; set; }
[XmlElement(ElementName = "data")]
public string data { get; set; }
[XmlElement(ElementName = "giveawayactive")]
public string giveawayactive { get; set; }
[XmlElement(ElementName = "giveawayserial")]
public string giveawayserial { get; set; }
[XmlElement(ElementName = "templates")]
public Templates Templates { get; set; }
[XmlAttribute(AttributeName = "xsi", Namespace = "http://www.w3.org/2000/xmlns/")]
public string Xsi { get; set; }
[XmlAttribute(AttributeName = "xsd", Namespace = "http://www.w3.org/2000/xmlns/")]
public string Xsd { get; set; }
}
[XmlRoot(ElementName = "templates")]
public class Templates
{
[XmlElement(ElementName = "template")]
public Template[] Template { get; set; }
}
[XmlRoot(ElementName = "template")]
public class Template
{
[XmlElement(ElementName = "id")]
public string id { get; set; }
[XmlElement(ElementName = "title")]
public string title { get; set; }
[XmlElement(ElementName = "type")]
public string type { get; set; }
}
码
...
var serializer = new XmlSerializer(typeof(LiveModelStruct));
var data = (LiveModelStruct)serializer.Deserialize(stream);
var test1 = data.version;
Debug.WriteLine(test1); //Returns 1 as it should
var test = data.Templates.Template[0].title; //Throws Error
Debug.WriteLine(test);
使用LINQ to XML解析您的XML。
XDocument doc = XDocument.Parse(xml);
var result = from c in doc.Descendants("LiveModelStruct")
select new LiveModelStruct()
{
version = (string)c.Element("version").Value,
live = (string)c.Element("live").Value
};
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