[英]how to call update file in ajax on index.php page
update.php页面
if (isset($_POST['bags']))
{
$bagS=$_POST['bags'];
$id=$_POST["id"];
$_SESSION['id']=$id;
$cats = explode(" ", $bagS);
$cats = preg_split('/,/', $bagS, -1, PREG_SPLIT_NO_EMPTY);
foreach($cats as $key => $cat )
{
$cat = mysqli_real_escape_string($con,$cats[$key]);
$cat = trim($cat);
if($cat !=NULL)
{
$stmt = $con->prepare('UPDATE wallet SET `Status`="Hold" where `Id`=? AND `bags`="'.$cat.'" ');
$stmt->bind_param("s", $_POST["id"]);
$stmt->execute();
}
}
}
想要在window.onbeforeunload
index.php页面上使用update.php文件
在这里使用ajax
function myfoo(){
$.ajax({
url: "update.php",
dataType: 'json',
data: {id: 1},
success: function (r) {}
});
}
window.onbeforeunload = function(){
myfoo();
return 'Are you sure you want to leave?';
};
1)您未发送任何数据,例如bag
2)ajax未定义类型:“ post”,但是您通过post访问的值。 如果未定义类型,则意味着ajax将使用默认的get方法。
$.ajax({
url: "update.php",
type:'post',
dataType: 'json',
data: {id: 1,bags:bags}, // bags collection value what your goging to send to server
success: function (r) {}
});
工作代码只是改变其中的一件事。 谢谢@JYoThI https://stackoverflow.com/users/5933698/jyothi
$.ajax({
url: "update.php",
type:'post',
dataType: 'json',
data: {
on_timeout: 1 // i just add this line
},
// bags collection value what your goging to send to server
success: function (r) {}
});
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