MySQLi Num行以检查行是否存在

Question

因此使用mysqli_num_rows来检查ID是否存在。 但现在它甚至没有加载。 但是它崩溃了我的脚本，不确定我丢失了什么，或者不确定是否编写正确。

任何帮助将不胜感激。 有时需要新鲜的眼睛才能看到一些小错误，我已经一遍又一遍地查找问题。

$get_oc = mysqli_fetch_assoc(mysqli_query($mysqli, "SELECT id from ap_oc where aff_id=$affiliate_id"));

if (mysqli_num_rows($get_oc) > 0) 
{
    $set_oc = mysqli_fetch_assoc(mysqli_query($mysqli, "SELECT commission from ap_oc where aff_id=$affiliate_id"));
    $comission = $set_oc['commission'];

    $get_tl_id = mysqli_fetch_assoc(mysqli_query($mysqli, "SELECT tl_id from ap_oc where aff_id=$affiliate_id"));
    $teamleaderid = $get_tl_id['tl_id'];

    $get_tl_oc = mysqli_fetch_assoc(mysqli_query($mysqli, "SELECT id from ap_oc where aff_id=$teamleaderid"));

        if (mysqli_num_rows($get_tl_oc) > 0) {
            $set_tl_oc = mysqli_fetch_assoc(mysqli_query($mysqli, "SELECT commission from ap_oc where aff_id=$teamleaderid"));
            $t2_comission = $set_tl_oc['commission'];
        } 
}

Answer 1

我完成了此代码所需的工作

   $get_oc = mysqli_fetch_assoc(mysqli_query($mysqli, "SELECT id from ap_oc where aff_id=$affiliate_id"));
    $count_oc = $get_oc['id'];
    if($count_oc==''){$count_oc = 0;}
     if ($count_oc > 0) 
        {

对于将来可能会有相同问题的任何人。