使用 HTTP 标头的 Spring Security

Question

我正在尝试为我的 Spring Boot 应用程序添加安全性。 我当前的应用程序正在使用 REST 控制器，每次收到GET或POST请求时，我都会读取 HTTP 标头以检索用户和密码，以便根据我存储的所有用户的属性文件来验证它们。 我想将其更改为使用 Spring Security，这就是我到目前为止所得到的：

public class SecurityConfig extends WebSecurityConfigurerAdapter {

    @Bean
    protected void configure(HttpSecurity http) throws Exception {
        http.authorizeRequests()
            .antMatchers("/index.html").permitAll()
            .antMatchers("/swagger-ui.html").hasRole("ADMIN")
            .anyRequest().authenticated();
    }

    @Bean
    public UserDetailsService userDetailsService() {
        InMemoryUserDetailsManager manager = new InMemoryUserDetailsManager();
        manager.createUser(User.withUsername("admin").password("password").roles("ADMIN").build());
    }
}

如何告诉configure方法是从标题中检索用户凭据，而不是从登录表单中检索？

Answer 1

最少的代码添加是定义一个过滤器并将其添加到安全配置中，smth like

XHeaderAuthenticationFilter.java

@Component
public class XHeaderAuthenticationFilter extends OncePerRequestFilter {

    @Override
    protected void doFilterInternal(HttpServletRequest request,
                                    HttpServletResponse response, FilterChain filterChain)
            throws ServletException, IOException {

        String xAuth = request.getHeader("X-Authorization");

        User user = findByToken(xAuth);

        if (user == null) {
            response.sendError(HttpServletResponse.SC_UNAUTHORIZED, "Token invalid");
        } else {
            final UsernamePasswordAuthenticationToken authentication =
                    new UsernamePasswordAuthenticationToken(user, null, user.getAuthorities());
            SecurityContextHolder.getContext().setAuthentication(authentication);

            filterChain.doFilter(request, response);
        }
    }

    //need to implement db user validation...
    private User findByToken(String token) {
        if (!token.equals("1234"))
            return null;

        final User user = new User(
                "username",
                "password",
                true,
                true,
                true,
                true,
                Collections.singletonList(new SimpleGrantedAuthority("ROLE_USER")));

        return user;
    }
}

安全配置.java

@Configuration
@EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {
    
        @Override
        protected void configure(final HttpSecurity http) throws Exception {
            http.sessionManagement()
                    .sessionCreationPolicy(SessionCreationPolicy.STATELESS)
                .and()
                .csrf().disable()
                .authorizeRequests().anyRequest().authenticated()
                .and()
                .exceptionHandling()
                    .authenticationEntryPoint(new HttpStatusEntryPoint(HttpStatus.UNAUTHORIZED))
                .and()
                .addFilterBefore(new XHeaderAuthenticationFilter(), UsernamePasswordAuthenticationFilter.class);
        }
}

另一种方法是使用spring的AOP在进入带注释的控制器方法之前定义一些要执行的逻辑的注释

Answer 2

您应该避免使用默认的org.springframework.security.web.authentication.UsernamePasswordAuthenticationFilter因为它从您的请求参数中获取客户端提供的用户名和密码，并且您确实需要从标头中获取它们。

因此，您应该编写一个自定义AuthenticationFilter扩展引用的UsernamePasswordAuthenticationFilter以更改其行为以满足您的要求：

public class HeaderUsernamePasswordAuthenticationFilter extends UsernamePasswordAuthenticationFilter {

  public HeaderUsernamePasswordAuthenticationFilter() {
    super();
    this.setFilterProcessesUrl("/**");
    this.setPostOnly(false);
  }

  /* (non-Javadoc)
   * @see org.springframework.security.web.authentication.UsernamePasswordAuthenticationFilter#obtainPassword(javax.servlet.http.HttpServletRequest)
   */
  @Override
  protected String obtainPassword(HttpServletRequest request) {
    return request.getHeader(this.getPasswordParameter());
  }

  /* (non-Javadoc)
   * @see org.springframework.security.web.authentication.UsernamePasswordAuthenticationFilter#obtainUsername(javax.servlet.http.HttpServletRequest)
   */
  @Override
  protected String obtainUsername(HttpServletRequest request) {
    return request.getHeader(this.getPasswordParameter());
  }

}

这个过滤器示例扩展了org.springframework.security.web.authentication.UsernamePasswordAuthenticationFilter监听每个请求并从 headers 而不是parameters获取username和password 。

然后您应该以这种方式更改配置，在UsernamePasswordAuthenticationFilter位置设置您的过滤器：

@Override
protected void configure(HttpSecurity http) throws Exception {
    http.addFilterAt(
                new HeaderUsernamePasswordAuthenticationFilter(), 
                UsernamePasswordAuthenticationFilter.class)
            .authorizeRequests()
            .antMatchers("/index.html").permitAll()
            .antMatchers("/swagger-ui.html").hasRole("ADMIN")
            .anyRequest().authenticated();

}

Answer 3

记忆中的身份验证将服务于您的目的

@Configuration
@EnableWebMvc
public class SecurityConfig extends WebSecurityConfigurerAdapter {

    @Override
    protected void configure(AuthenticationManagerBuilder auth) throws Exception {
        auth.inMemoryAuthentication()
        .withUser("user1").password("password1").roles("USER")
        .and()
        .withUser("user2").password("password2").roles("ADMIN");
    }

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http.authorizeRequests().anyRequest().fullyAuthenticated();
        http.httpBasic();   
    }

}

Answer 4

在 Spring Boot 应用程序中，您可以将以下内容添加到 application.properties

security.user.name=user
security.user.password=password

它会做剩下的事情，比如从标题和验证中获取更多访问https://docs.spring.io/spring-boot/docs/current/reference/html/boot-features-security.html