Android Google oAuth2“/oauth2/v4/token”请求显示未找到异常文件

Question

应用程序需要谷歌刷新令牌，我尝试调用基于谷歌 OAuth2 文档的服务。

https://developers.google.com/identity/protocols/OAuth2InstalledApp

第 5 步：交换刷新和访问令牌的授权代码

服务抛出异常。

“java.io.FileNotFoundException： https : //www.googleapis.com/oauth2/v4/token ”

使用服务，如：

POST /oauth2/v4/token HTTP/1.1 主机：www.googleapis.com 内容类型：application/x-www-form-urlencoded

代码=4/P7q7W91a-oMsCeLvIaQm6bTrgtp7& client_id=your_client_id& client_secret=your_client_secret& redirect_uri= https://oauth2.example.com/code& grant_type=authorization_code

示例代码：

class getTokenAsyncTask extends AsyncTask<String, Void, String> {

        @Override
        protected String doInBackground(String... params) {
            String JsonResponse = "";
            BufferedReader reader = null;
            HttpURLConnection urlConn;

            try {
                URL url = new URL("https://www.googleapis.com/oauth2/v4/token");
                String client_id = "******9-tt3qav2d2rp45sgjqp5helrsbvc22kdq.apps.googleusercontent.com";
                String client_secret = ""; //This value is not needed for clients registered as Android, iOS, or Chrome applications.
                String redirect_uri = "http://localhost";
                String grant_type = "authorization_code";
                String code = params[0]; // serverAuthCode code
                HashMap<String, String> params1 = new HashMap<String, String>();
                params1.put("client_id", client_id);
                params1.put("client_secret", client_secret);
                params1.put("grant_type", grant_type);
                params1.put("redirect_uri", redirect_uri);
                params1.put("code", code);  // your code received

                Set set = params1.entrySet();
                Iterator i = set.iterator();
                StringBuilder postData = new StringBuilder();
                for (Map.Entry<String, String> param : params1.entrySet()) {
                    if (postData.length() != 0) {
                        postData.append('&');
                    }
                    postData.append(URLEncoder.encode(param.getKey(), "UTF-8"));
                    postData.append('=');
                    postData.append(URLEncoder.encode(String.valueOf(param.getValue()), "UTF-8"));
                }
                byte[] postDataBytes = postData.toString().getBytes("UTF-8");

                HttpsURLConnection conn = (HttpsURLConnection) url.openConnection();
                conn.setRequestMethod("GET");
                conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
                conn.setRequestProperty("Content-Length", String.valueOf(postDataBytes.length));
                conn.setDoOutput(true);
                conn.getOutputStream().write(postDataBytes);
                reader = new BufferedReader(new InputStreamReader(conn.getInputStream(), "UTF-8"));
                StringBuilder builder = new StringBuilder();
                for (String line = null; (line = reader.readLine()) != null; ) {
                    builder.append(line).append("\n");
                }
                reader.close();
                conn.disconnect();
                System.out.println("token returned: " + builder.toString());

            } catch (MalformedURLException e) {
                e.printStackTrace();
            } catch (Exception e) {
                e.printStackTrace();
            }
            return null;
        }
    }

请建议我，如何在 android 应用程序中调用服务和接收刷新令牌 ID。

Answer 1

conn.setRequestMethod("GET");

应该是

conn.setRequestMethod("POST");

因为您正在发送发布请求。