如何在php中将变量一页传递给另一页
[英]How to pass Variable One page to another in php
问题描述
我创建了动态按钮，并且单击按钮时需要将按钮ID传递到另一页。 我通过了，但是没用
请给出任何解决方案
这是我的dash.php代码：
<?php
session_start();
function dash () {
include 'config.php';
$sql = "SELECT RoomNumber FROM roommaster ";
if ($result = mysqli_query($db, $sql)) {
$str = '';
while ($row = mysqli_fetch_array($result)) {
// generate array from comma delimited list.
$rooms = explode(',', $row['RoomNumber']);
//create the dynamic button and set the value.
foreach ($rooms as $v) {
$str .= "<a href = 'booking.php'?btn='btn'><input type='button' name='b1' id='btn' value='" . $v . "' /></a>";
}
}
return $str;
} else {
echo "ERROR: Could not able to execute $sql. " . mysqli_error($db);
}
mysqli_close($db);
}
这是我的booking.php页面：
<?php
if (isset($_POST['btn'])) {
$btn = $_POST['btn'];
echo $btn;
}
$sql = "SELECT RoomNumber FROM roommaster where RoomId=' " . $_GET['btn'] . " '";
if ($result = mysqli_query($db, $sql)) {
if (mysqli_num_rows($result) > 0) {
while ($row = mysqli_fetch_array($result)) {
$RoomNumber = $row['RoomNumber'];
// $RoomType=$row['RoomType'];
// $Location=$row['Location'];
// $ChargesPerDay=$row['ChargesPerDay'];
}
// Free result set
mysqli_free_result($result);
} else {
echo "No records matching your query were found.";
}
} else {
echo "ERROR: Could not able to execute $sql. " . mysqli_error($db);
}
mysqli_close($db);
?>
HTML：
<html lang="en">
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1">
<!-- The above 3 meta tags *must* come first in the head; any other head content must come *after* these tags -->
<title>Customer book Form</title>
<!-- Bootstrap -->
<link href="css/bootstrap1.min.css" rel="stylesheet">
<link href="css/book.css" rel="stylesheet">
<script src='http://cdnjs.cloudflare.com/ajax/libs/jquery/2.1.3/jquery.min.js'></script>
<link rel="stylesheet" href="https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.4/themes/smoothness/jquery-ui.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.4/jquery-ui.min.js"></script>
</style>
<!-- jQuery (necessary for Bootstrap's JavaScript plugins) -->
<script src="js/jquery-1.12.4.js"></script>
<script src="js/book1.js"></script>
<!-- Include all compiled plugins (below), or include individual files as needed -->
<script src="js/bootstrap.min.js"></script>
</head>
<body>
<div class="head" id="link">
<div class="panel panel-primary" style="margin:20px;">
<div class="panel-heading">
<center><h3 class="panel-title"> Customer booking Form</h3></center>
</div>
<div class="panel-body">
<form method="post" action="">
<div class="col-md-12">
<div class="form-group col-md-12 ">
<label for="roomno">Room Number* </label>
<input type="text" class="form-control input-sm" name="RoomNumber" value="<?=$_GET['btn'];?>"required>
</div>
<div class="form-group col-md-6">
<label for="type">Room Type*</label>
<input type="text" class="form-control input-sm" name="RoomType" required >
</div>
<div class="form-group col-md-6">
<label for="location">Location*</label>
<input type="text" class="form-control input-sm" name="Location" required>
</div>
<div class="form-group col-md-12">
<label for="charges">Facilities*</label>
<input type="text" class="form-control input-sm" name="Facilities" required>
</div>
<div class="form-group col-md-12">
<label for="charges">ChargesPerDay*</label>
<input type="text" class="form-control input-sm" name="ChargesPerDay" required>
</div>
<div class="form-group col-md-4">
<label for="customer name">First Name*</label>
<input type="text" class="form-control input-sm" name="FirstName" required>
</div>
</div>
</form>
</div>
</body>
</html>
5 个解决方案
解决方案1
1 2017-05-31 07:01:55
尝试使用$ _GET代替$ _POST
if (isset($_GET['btn'])) {
$btn = $_GET['btn'];
echo $btn;
}
解决方案2
1 2017-05-31 07:04:49
尝试使用表单链接。 BUTTONID应该是要传递的值。 $ str应该是：
<form action='booking.php' method='POST'>
<input type='hidden' value='BUTTONID' name='bttn'>
<input type='submit' value='".$v."'>
</form>
然后像您已经获得的那样获取隐藏字段的值...
$if (isset($_POST['bttn'])) {
$btn = $_POST['bttn'];
echo $btn;
}
解决方案3
1 2017-05-31 07:15:47
我修改了dash.php和booking.php文件的脚本。 请复制并粘贴此脚本。
dash.php文件
<?php
session_start();
function dash(){
include 'config.php';
$sql = "SELECT RoomNumber FROM roommaster ";
if($result = mysqli_query($db, $sql))
{
$str = '';
while($row = mysqli_fetch_array($result))
{
// generate array from comma delimited list
$rooms = explode(',', $row['RoomNumber']);
//create the dynamic button and set the value
foreach ( $rooms as $v )
{
$str .= "<a href='booking.php'?btn="'.$v.'"><input type='button' name='b1' id='btn' value='".$v."' /></a>";
}
}
return $str;
}
else {
echo "ERROR: Could not able to execute $sql. " .mysqli_error($db);
}
mysqli_close($db);
booking.php文件
$sql = "SELECT RoomNumber FROM roommaster where RoomId=' " .$_GET['btn']." '";
if($result = mysqli_query($db, $sql)){
if(mysqli_num_rows($result) > 0){
while($row = mysqli_fetch_array($result)){
$RoomNumber=$row['RoomNumber'];
//$RoomType=$row['RoomType'];
// $Location=$row['Location'];
// $ChargesPerDay=$row['ChargesPerDay'];
}
// Free result set
mysqli_free_result($result);
} else{
echo "No records matching your query were found.";
}
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($db);
}
mysqli_close($db);
解决方案4
0 2017-05-31 07:04:47
尝试使用$_REQUEST来获取GET和POST值。在booking.php中，打印如下数组：
print_r($_REQUEST);
if (isset($_REQUEST['btn'])) {
$btn = $_REQUEST['btn'];
echo $btn;
}
解决方案5
0 2017-05-31 07:08:57
要将少量数据从一页传递到另一页，请使用以下URL中的parameter ，该parameter是要传递给下一页的value parameter ：
<a href="anotherpage.php?parameter=value">Click Button</a>
然后在anotherpage.php上，使用$_GET获得URL传递的值，如下所示：
$val = isset($_GET['parameter']) ? $_GET['parameter'] : NULL;
然后将$val用于其他处理。 我认为这可以帮助您了解如何简单地将data从一页传递到另一页。
PHP / JavaScript：如何将变量从一页传递到另一页
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