在HIVE中按字段分组以使用Hive获取所有列

Question

我有以下数据集，我想基于特定列上的分组依据（或某些其他功能）获得特定列值。 我的数据集如下所示：

id  zip  Action  content  duration  OS    TIME
================================================
1  11    START   DELL               LINUX   12
1  11    JUMP    HP                 UNIX    14
1  11    STOP    HP       10        LINUX   16
1  11    START   WIN               LINUX    2
1  11    JUMP    HP                 UNIX    4
1  11    STOP    SONY     12        LINUX   15
2  12    START   HP                 UNIX    3
2  12    STOP    FOP      2         WINDOWS 10
--------------------------------------------

我想获得基于相同（id，zip）组的所有列值，其中Action ='STOP'和已过滤记录的最大时间。 我的预期输出将是：

id  zip  Action  content  duration  OS
========================================
1  11    STOP    HP       10        LINUX

2  12    STOP    FOP      2         WINDOWS
--------------------------------------------

我如何使用HIVE达到同样的目的？ 请帮忙。

Answer 1

row_number

select  id,zip,Action,content,duration,OS

from   (select  *
               ,row_number() over
                (
                    partition by    id,zip
                    order by        time desc
                )   as rn

        from    mytable

        where   action = 'STOP'
        ) t

where   rn = 1

---

+----+-----+--------+---------+----------+---------+
| id | zip | action | content | duration |   os    |
+----+-----+--------+---------+----------+---------+
|  1 |  11 | STOP   | HP      |       10 | LINUX   |
|  2 |  12 | STOP   | FOP     |        2 | WINDOWS |
+----+-----+--------+---------+----------+---------+