每个对象的功能如何

Question

没有结果数据，如何通过提供名称从名称数组中的对象之一获取数据？ 以及用于列表查询和显示的类信息。

 $.when(Data('')).then(function(result) { var results = result.d.results; var html = ""; html = "<table>"; $.each(results, function(key, fila) { console.log("Data ", fila); //no result html += "<tr>"; html += "<td>" + lack name + "</td><td>" + lack occupation + "</td>"; html += "</tr>"; }); html += "</table>"; $(".info").html(html); }); function Data() { //how to get object name var person = { name: "Tahir Akhtar", occupation: "Software Development" }; var p1 = "name"; var p2 = "occupation"; alert(person[p1]); alert(person[p2]); } 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div class="info"></div> 

Answer 1

您需要从函数中返回对象。 然后将其返回对象将是result在.then()回调函数。 然后，您可以使用$.each()遍历属性。

 $.when(Data()).then(function(result) { var html = ""; html = "<table>"; var headerRow = ""; var dataRow = ""; $.each(result, function(key, fila) { console.log("Data ", fila); //no result headerRow += "<th>" + key + "</th>"; dataRow += "<td>" + fila + "</td>"; }); html += "<tr>" + headerRow + "</tr>"; html += "<tr>" + dataRow + "</tr>"; html += "</table>"; $(".info").html(html); }); function Data() { //how to get object name var person = { name: "Tahir Akhtar", occupation: "Software Development" }; var p1 = "name"; var p2 = "occupation"; alert(person[p1]); alert(person[p2]); return person; } 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div class="info"></div>