如何使用Google Apps脚本获取数组中值的索引

Question

function convertToEnts(formObject){
  var sheet = SpreadsheetApp.getActiveSheet();
  var columns = sheet.getRange(1,1,1, sheet.getLastColumn()).getValues()[0];
  var columnValues = String(columns).split(",");  //this is something I tried on the advise of https://stackoverflow.com/questions/17044825/indexof-returning-1-despite-object-being-in-the-array-javascript-in-google-sp
  var data = sheet.getRange(2, 1,sheet.getLastRow()-1,sheet.getLastColumn()).getValues();
  for (var i=0;data.length;i++){
    row = data[i];
    var entity = {}
    //formObject: {identity=lat,...,other form attributes here}
    for (var key in formObject){
      Logger.log(formObject[key]);
      Logger.log(typeof formObject[key]);
      Logger.log(columnValues);    
      var indexOfKey = columnValues.indexOf(formObject[key]);
      Logger.log(indexOfKey);
      var value = formObject[key];    //row[indexOfTimestamp]
      entity[key] = row[indexOfKey];
    }
  }
}

日志：

[17-06-15 15:48:02:071 PDT] lat 
[17-06-15 15:48:02:072 PDT] string
[17-06-15 15:48:02:072 PDT] [a, b, c, lat]
[17-06-15 15:48:02:073 PDT] -1.0

因此formObject [key]或value是lat。 类型是一个字符串（到目前为止一切正常）。 该列看起来像[a，b，c，lat]。 我基本上想返回lat的索引，我认为应该是3。 我正在努力解决该indexOfKey变量。 我尝试的任何结果都将返回-1，就好像字符串不在数组中一样。 有什么建议么？

Answer 1

这实际上是一个已知的错误（ 在Google的问题跟踪器中有一张票 ）。

最简单的解决方法是将以下polyfill添加到您的代码中（ 源自MDN ）。

// Production steps of ECMA-262, Edition 5, 15.4.4.14
// Reference: http://es5.github.io/#x15.4.4.14
if (!Array.prototype.indexOf) {
  Array.prototype.indexOf = function(searchElement, fromIndex) {

    var k;

    // 1. Let o be the result of calling ToObject passing
    //    the this value as the argument.
    if (this == null) {
      throw new TypeError('"this" is null or not defined');
    }

    var o = Object(this);

    // 2. Let lenValue be the result of calling the Get
    //    internal method of o with the argument "length".
    // 3. Let len be ToUint32(lenValue).
    var len = o.length >>> 0;

    // 4. If len is 0, return -1.
    if (len === 0) {
      return -1;
    }

    // 5. If argument fromIndex was passed let n be
    //    ToInteger(fromIndex); else let n be 0.
    var n = fromIndex | 0;

    // 6. If n >= len, return -1.
    if (n >= len) {
      return -1;
    }

    // 7. If n >= 0, then Let k be n.
    // 8. Else, n<0, Let k be len - abs(n).
    //    If k is less than 0, then let k be 0.
    k = Math.max(n >= 0 ? n : len - Math.abs(n), 0);

    // 9. Repeat, while k < len
    while (k < len) {
      // a. Let Pk be ToString(k).
      //   This is implicit for LHS operands of the in operator
      // b. Let kPresent be the result of calling the
      //    HasProperty internal method of o with argument Pk.
      //   This step can be combined with c
      // c. If kPresent is true, then
      //    i.  Let elementK be the result of calling the Get
      //        internal method of o with the argument ToString(k).
      //   ii.  Let same be the result of applying the
      //        Strict Equality Comparison Algorithm to
      //        searchElement and elementK.
      //  iii.  If same is true, return k.
      if (k in o && o[k] === searchElement) {
        return k;
      }
      k++;
    }
    return -1;
  };
}