多个字段上的数组过滤

Question

我有这个代码，它过滤我的数据。 我问我，是否有办法不明确过滤每个字段（ id 、 mandant 、 zonenlogik ...）。 也许有一种更流畅的方法来在所有字段上设置过滤器而不显式调用它们？

let filteredList = this.state.freights.filter((freight) => {

    if (freight.id.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
        return freight;
    }
    if (freight.mandant.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
        return freight;
    }
    if (freight.zonenlogik.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
        return freight;
    }
    if (freight.frachtart_nr.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
        return freight;
    }
    if (freight.transportart_nr.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
        return freight;
    }
    if (freight.spedit_nr.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
        return freight;
    }
    if (freight.spedit2_nr.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
        return freight;
    }
    if (freight.lager_nr.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
        return freight;
    }
});

Answer 1

您可以使用Object.values()获取对象值，然后遍历这些值以检查字符串中是否存在子字符串，然后返回过滤后的对象

let filteredList = this.state.freights.filter((freight) => {
    let search = this.state.search.toLowerCase();
    var values = Object.values(freight);
    var flag = false
    values.forEach((val) => {
      if(val.toLoweCase().indexOf(search) > -1) {
           flag = true;
           return;
       }
     }
     if(flag) return freight
});

Answer 2

我假设您想要另一个与您发布的代码实现相同结果的代码。 这是我的：

 const searchTerm = this.state.search.toLowerCase(); let filteredList = this.state.freights.filter((freight) => { // get all keys of freight const keys = Object.keys(freight).map(k => k.toLowerCase()); for (let k of keys) { // if key (eg id) matches the search term, return freight if (k.indexOf(searchTerm) !== 1) { return true; // we want this freight object } } return false; });

Answer 3

这是 es5 单行（有点）：

let filteredList = this.state.freights.filter(freight =>
  Object.keys(freight).some(
    key =>
      freight[key]
        .toLowerCase()
        .indexOf(this.state.search.toLowerCase()) !== -1,
  ),
);