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从Firebase中删除,notifyDataSetChanged(); 不刷新ListView

[英]Deleting from Firebase, notifyDataSetChanged(); doesn't refresh ListView

基本上从Firebase中删除Object后, notifyDataSetChanged()不会实时更新它。 我试图从适配器本身删除对象,但它也失败了。

回到这个片段显示更新的列表,但我认为这是因为添加了孩子。 这是我的代码。

public class ArchiveFragment extends Fragment {

    public static ArchiveFragment newInstance(Beer beer) {
        ArchiveFragment archiveFragment = new ArchiveFragment();
        if (beer != null) {
            Bundle args = new Bundle();
            args.putSerializable("beer", beer);
            archiveFragment.setArguments(args);
        }
        return archiveFragment;
    }

    public ArchiveFragment(){}

    private ArrayList<Beer> beerDB = new ArrayList<>();
    private ListView beerList;
    private RecyclerView beerRec;
    private DatabaseReference mDatabase;

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
                             Bundle savedInstanceState) {
        final View view = inflater.inflate(R.layout.archive_fragment, container, false);
        final Activity activity = getActivity();
        FirebaseUser user = FirebaseAuth.getInstance().getCurrentUser();
        beerList = (ListView)view.findViewById(R.id.beerList);
        final ArrayAdapter<Beer> arrayAdapter = new ArrayAdapter<Beer>(getActivity(), android.R.layout.simple_list_item_1,beerDB);
        mDatabase = FirebaseDatabase.getInstance().getReference().child("Users").child(user.getUid()).child("BeerList");
        beerList.setAdapter(arrayAdapter);

        beerList.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> adapterView, View view, int i, long l) {
                Object deletedBeer = beerList.getItemAtPosition(i);
                Beer delBeer = (Beer) deletedBeer;
                deleteBeer(delBeer.getKey());
            }
        });

        mDatabase.addChildEventListener(new ChildEventListener() {
            @Override
            public void onChildAdded(DataSnapshot dataSnapshot, String s) {
                Beer value = dataSnapshot.getValue(Beer.class);
                value.setKey(dataSnapshot.getKey());
                beerDB.add(value);

                arrayAdapter.notifyDataSetChanged();
            }

            @Override
            public void onChildChanged(DataSnapshot dataSnapshot, String s) {}

            @Override
            public void onChildRemoved(DataSnapshot dataSnapshot) {

                String key = dataSnapshot.getKey();
                beerDB.remove(key);
                arrayAdapter.notifyDataSetChanged();
            }

            @Override
            public void onChildMoved(DataSnapshot dataSnapshot, String s) {}

            @Override
            public void onCancelled(DatabaseError databaseError) {}
        });

        return view;
    }

    public void deleteBeer(String key){
        mDatabase.child(key).removeValue();
    }
}

您正在使用不正确的remove函数从ArrayListremove该项。 remove函数获取ArrayList中需要删除的项的索引。 但是在这里,当您从dataSnapshot获取密钥时,它与您的ArrayList任何索引都不匹配,因此该项目实际上并未从您的ArrayList删除。 所以你需要像这样改变你的onChildRemoved函数。

@Override
public void onChildRemoved(DataSnapshot dataSnapshot) {

    String key = dataSnapshot.getKey();

    for (int i = 0; i < beerDB.size(); i++) {
        // Find the item to remove and then remove it by index
        if (beerDB.get(i).key.equals(key)) {
            beerDB.remove(i);
            break;
        } 
    }

    arrayAdapter.notifyDataSetChanged();
}

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